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mixer [17]
4 years ago
6

What is the maximum velocity that a 0.3–kilogram mass attached to a 0.75–meter string can have if the mass is whirled around in

a circular horizontal path? The maximum tension that the string can withstand is 250 newtons.
Physics
1 answer:
Novay_Z [31]4 years ago
6 0
Since this is a horizontal path, we can neglect the force of gravity acting on the body. So in this case we have that the force of tension is equal to the centripetal force, because we have a circular path. 

Fcp=T, where T is the force of tension and Fcp is the centripetal force. 

m*(v²/R)=250 N, where m is the mass of the body and it is m=0.3 kg, v is the max speed of the body, and that is what we are looking for and R is the max length of the string and it is R=0.75 m. 

We divide by m and multiply by R and we get:

v²=(250*R)/m, take the square root:

v=√((250*R)/m)=25 m/s

So the max speed of the body if the max tension is T= 250 N and its max length is R=0.75 m is V=25 m/s. 
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Which statements can be supported by using a position-time graph? Check all that apply. A negative slope results when an individ
Naya [18.7K]

A negative slope results when an individual is moving toward the origin.

A positive slope results when an individual is moving away from the origin.

The slope of the line gives the velocity of the individual.

Explanation:

In a position-time graph, the position is represented on the y-axis (distance from the origin), while the time is represented on the x-axis. Let's analyze each statement:

A negative slope results when an individual is moving toward the origin. --> TRUE. In fact, a negative slope means that the value on the y is decreasing as the time passes, so the distance of the individual is decreasing as the time increases, therefore the person is moving towards the origin.

A horizontal line on the graph means the individual is moving at the same velocity. --> FALSE. A horizontal line means that the position of the individual is constant, so the person is not moving.

A positive slope results when an individual is moving away from the origin. --> TRUE. In this case, the value on the y is increasing with time, so the distance of the person from the origin is increasing with time.

The slope of the line gives the velocity of the individual. --> TRUE. In a position-time graph, the velocity of the individual is equal to the ratio between the displacement and the time taken. But the displacement corresponds to the increase in the y-value, while the time corresponds to the increase in the x-value, so the velocity corresponds to the slope of the graph. In order to know velocity, we must also know the direction of the motion.

The speed of an individual cannot be determined from this type of graph. --> FALSE. The speed is equal to the slope of the position-time graph (in fact, the speed is the magnitude of the velocity)

8 0
4 years ago
Read 2 more answers
If you were on a decision making board with the task of choosing which innovation to fund, what criteria would you use to make y
faust18 [17]

Explanation:

The criteria for decision making would be

1. I would fund for the school of young diabetics, for the sole purpose of them leaning and being motivated for a healthy lifestyle.

2. I would also fund for new and improved insulin pumps as old ones cause multiple problems.

3 0
3 years ago
The number of times that a wave vibrates in unit is called
kari74 [83]
I believe it's frequency. 
6 0
4 years ago
A heavy solid disk rotating freely and slowed only by friction applied at its outer edge takes 120 seconds to come to a stop.
alisha [4.7K]

Answer:

The time is 16 min.

Explanation:

Given that,

Time = 120 sec

We need to calculate the moment of inertia

Using formula of moment of inertia

I=\dfrac{1}{2}MR^2

If the disk had twice the radius and twice the mass

The new moment of inertia

I'=\dfrac{1}{2}\times2M\times(2R)^2

I'=8I

We know,

The torque is

\tau=F\times R

We need to calculate the initial rotation acceleration

Using formula of acceleration

\alpha=\dfrac{\tau}{I}

Put the value in to the formula

\alpha=\dfrac{F\times R}{\dfrac{1}{2}MR^2}

\alpha=\dfrac{2F}{MR}

We need to calculate the new rotation acceleration

Using formula of acceleration

\alpha'=\dfrac{\tau}{I'}

Put the value in to the formula

\alpha=\dfrac{F\times R}{8\times\dfrac{1}{2}MR^2}

\alpha=\dfrac{2F}{8MR}

\alpha=\dfrac{\alpha}{8}

Rotation speed is same.

We need to calculate the time

Using formula angular velocity

\Omega=\omega'

\alpha\time t=\alpha'\times t'

Put the value into the formula

\alpha\times120=\dfrac{\alpha}{8}\times t'

t'=960\ sec

t'=16\ min

Hence, The time is 16 min.

5 0
3 years ago
Predict the speed of a car after 10.0 s when the car’s speed follows
andreev551 [17]

Answer:

48 m/s

Explanation:

The time is 10 seconds

The speed of the car after 10 seconds when the relationship is 4.8 m/s^2 × time can be calculated as follows

= 4.8 × 10

= 48

Hence the speed is 48 m/s

7 0
4 years ago
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