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NARA [144]
3 years ago
10

Give 5 examples of physical properties that could be used to describe a solid

Physics
1 answer:
ycow [4]3 years ago
8 0
1.) appearance
2.)texture
3.)color
4.)melting point
5.)odor
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1) A pendulum is configured to have a period of 2 seconds.
vazorg [7]

"The" (and any subsequent words) was ignored because we limit queries to 32 words.

3 0
3 years ago
A cart with a mass of 0.5 kg is at the top of the ramp. The height is 0.40m .
Tju [1.3M]

A=0.05.0M.

B=68.9244GPE.34

C=0

D it would be 79%HIGHER

3 0
3 years ago
Two cannonballs are dropped from a second-floor physics lab at height h above the ground. Ball B has four times the mass of ball
denpristay [2]

Answer:

1:4

Explanation:

The formula for calculating kinetic energy is:

KE=\dfrac{1}{2}mv^2

If the mass is multiplied by 4, then, the kinetic energy must be increased by 4 as well. Since they will be travelling at the same speed when they are at the same point, the relation between KA and KB must be 1:4 or 1/4. Hope this helps!

3 0
3 years ago
In Mendel’s day, many people thought that offspring inherited a blend of their parents’ traits. For example, they thought that a
Fantom [35]

Answer:

Explanation:In Mendel's time, many people thought that offspring inherited a combination of traits from their parents. For example, they thought that an animal with white fur and an animal with black fur would produce pups with gray fur. This is called the theory of combined inheritance. How did Mendel show that the combination theory was wrong?

6 0
3 years ago
A small plane flies 40.0 km in a direction 60° north of east and then flies 30.0 km in a direction 15° north of east. Use the an
lana66690 [7]

Answer:

d= 64.7 km

\theta = 40.9^{o}

displacement vector=r_xi + r_yj =  48.9i + 42.4j

Explanation:

total distance = 40 + 30 = 70 km

during 1st flight

r_1 x = 40*cos60

r_1 x = 20 km

r_1 y = 40*sin60

r_1 y = 34.64 km

during 2nd flight

r_2 x = 30*cos15

r_2 x = 28.9 km

r_2 y = 30*sin15

r_2 y = 7.76 km

the two component of r are:

r_x = r_1x + r_2x = 20 + 28.9 = 48.9 km

r_y = r_1y + r_2y = 34.64 + 7.76 = 42.4 km

Geographical Direction \theta = tan^{-1}\frac{r_y}{r_x} [tex]\theta = 40.9^{o}

Displacement d= \sqrt{r_x^2 + r_y^2}

                     d = \sqrt{48.9^2+42.4^2} = 64.7 km

d= 64.7 km

displacement vector=r_xi + r_yj =  48.9i + 42.4j

8 0
3 years ago
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