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puteri [66]
3 years ago
6

7=11t

Mathematics
2 answers:
shtirl [24]3 years ago
7 0

We move all terms to the left:

7-(11t)=0

We move all terms containing t to the left, all other terms to the right

-11t=-7

t=-7/-11

t=7/11

joja [24]3 years ago
5 0

Steps to solve:

7 = 11t

~Divide 11 to both sides

7/11 = 11t/11

~Simplfy

7/11 = t

The fraction can't be simplified any further.

Best of Luck!

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Do you want the answer or it written out? The written out would be down below and the answer is also down below in the x to the power of x equals 8/3 and its written out.

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Please help me with this question!!!!!
Naddika [18.5K]

Answer:

7/25

Step-by-step explanation:

θ lies in quadrant ii

so 2θ lies in quadrant iv

csc θ=5/3

sin θ=3/5 (sin θ=1/csc θ)

[cos(α+β)=cosαcosβ-sinαsinβ]

cos (2θ)=cos(θ+θ)=cos θ cos θ-sin θ sin θ=cos² θ-sin ²θ=1-sin²θ-sin²θ=1-2sin²θ

=1-2 (3/5)²

=1-2(9/25)

=1-18/25

=(25-18)/25

=7/25

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gregori [183]

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54%

Step-by-step explanation:

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How many different factors does 25 have
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7 0
3 years ago
Read 2 more answers
Please asap<br>for 10 points!​
kari74 [83]
<h3>Given:</h3><h3>Large cone:</h3>
  • r= 8 cm
  • h= 20 cm
<h3>Small cone:</h3>
  • r= 4 cm
  • h= 10cm
<h3>Note that:</h3>
  • r: radius
  • h: height
<h3>To find:</h3>
  • The volume of the frustum of the given cone.
<h3>Solution:</h3>
  • Frustum is a part of a cone formed by cutting off the top by a parallel plane.

\large\boxed{Formula: V= \frac{1}{3}\pi{r}^{2}h}

Let's solve!

First, let's find the volume of the smaller cone.

Substitute the values according to the

formula.

V= \frac{1}{3}×\pi×{4}^{2}×10

V= 167.5516082 \: {cm}^{3}

Now, we can round off to the nearest hundredth.

The value in the thousandths place is smaller than 5 so we won't have to round up.

\boxed{V= 167.55 \: {cm}^{3}}

Next, let's find the volume of the bigger cone.

Substitute the values according to the formula.

V= \frac{1}{3}×\pi×{8}^{2}×20

V= 1340.412866 \: {cm}^{3}

Now, we can round off to the nearest hundredth.

The value in thousandths place is smaller than 5 so we won't have to round up.

\boxed{V=1340.41 \: {cm}^{3}}

Now, we can find the volume of the frustum.

We'll have to minus the volume of the smaller cone from the bigger cone.

V= 1340.41-167.55

\large\boxed{V= 1172.86 \: {cm}^{3}}

<u>Hence, the volume of the frustum is 1172.86 cubic centimeters.</u>



8 0
2 years ago
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