Answer:
ㅋㅋㅋㅋㅋㅋㅋㅋㅋㅋㅋㅋ:)
Step-by-step explanation:
Answer:
The ball will take 1 sec
Step-by-step explanation:
∵ The distance from the ground when the ball leaves = 6 ft
∵ The distance from the ground when the ball catches = 10 ft
∴ The difference between two position = 10 - 6 = 4 ft
∵ s = ut - 1/2 at² ⇒ s is the distance , u is the initial velocity , a is acceleration of gravity and t is the time
∵ s = 4 feet , u = 20 feet/sec and a ≅ 32 feet/sec²
∴ 4 = 20t -32/2 t²
∴ 16t² - 20t + 4 = 0
∴ (4t - 4)(4t - 1) = 0
∴ 4t - 4 = 0 ⇒ t = 1 and 4t - 1 = 0 ⇒ t = 1/4
∴ The ball will take 1 sec to go from first player to the second player
Note: 1/4 sec is the time of the ball after leaves the position of the first player by 4 feet above the initial position.
Answer:
HAVE A NICE DAY :)))
Step-by-step explanation:
thank
So x + y = 45, and 4x + 5y = 195. Get y by itself. Subtract x from both sides in the first equation to get y = 45 -x, and subtract 4x from the second equation to get 5y = 195 - 4x. Divide by 5 to both sides to get y = 39 - 4/5x. 39 - 4/5x = 45 - x. Add x to both sides to get 39 - 1/5x = 45. Subtract 39 from both sides to get -1/5x = 6. Divide by -1/5 to get x = -30, or 30. In the first equation, do 30 + y = 45. Subtract 30 from both sides to get y = 15. Check. 4(30) + 15(5) = 195, or 120 + 75 = 195.
