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Lesechka [4]
3 years ago
15

Let set C = {even numbers between 1 and 99} and set D = {numbers between 1 and 150 that are evenly divisible by 10}.

Mathematics
1 answer:
Alex3 years ago
4 0
C=\{2;\ 4;\ 6;\ 8;\ ...;\ 98\}\\\\D=\{10;\ 20;\ 30;\ 40;\ 50;\ 60;\ ...;\ 140\}\\\\C\ \cap\ D=\{10;\ 20;\ 30;\ 40;\ 60;\ 70;\ 80;\ 90\}\\\\Answer:\boxed{A}
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What is the answer to this equation |x−1|+5=2
barxatty [35]

Answer:

No solutions

Step-by-step explanation:

Isolate the absolute value:

|x−1| + 5 = 2

Subtract 5 from both sides:

|x-1| = -3

Since an absolute value can never be equal to a negative number, there are no solutions.

6 0
3 years ago
Read 2 more answers
Suppose an ant walks counterclockwise on the unit circle from the point to the endpoint of the radius that forms an angle of rad
serg [7]

Answer:

\frac{4\pi}{3}

Step-by-step explanation:

The original questions is suppose an ant walks counterclockwise on a unit circle from the point (1,0) to the endpoint of the radius that forms an angle of 240 degrees with the positive horizontal axis.

To find the distance ant walked we find the arc length of the sector with central angle 240 degree and radius =1 (unit circle)

arc length of a sector =\frac{centralangle}{360} \cdot 2\pi r

arc length of a sector =\frac{240}{360} \cdot 2\pi(1)

arc length of a sector =\frac{2}{3} \cdot 2\pi

\frac{4\pi}{3}

6 0
3 years ago
Someone please help me
Troyanec [42]
Pythagorean theorem is a^{2} + b^{2} = c^{2}
and using that sin is opposite/hypotenuse, you can find the third side of the triangle.
11^{2}+(adjacent)^{2} = 61^{2} \\ 121+ (adjacent)^{2} = 3721 \\ (adjacent)^{2}=3600 \\ adjacent = 60
now you know adjacent is 60, so cos=60/61
4 0
3 years ago
A triangle can exist with side lengths 15cm, 22cm, and 35cm.<br> A<br> False<br> B<br> True
Advocard [28]

Answer:

The answer is False maybe

8 0
3 years ago
Solve the inequality 5(2h+8)&lt;60
zimovet [89]

Answer:

<h2>h < 2</h2>

Step-by-step explanation:

5(2h+8) < 60

Expand the terms in the bracket

We have

10h + 40 < 60

Group like terms

10h < 60 - 40

10h < 20

Divide both sides by 10

h < 2

Hope this helps you

7 0
3 years ago
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