Answer:
I assume you know Arithmetic Progression .
so, we have to find the first and last 4-digit number divisible by 5
first = 1000 , last = 9990
we have a formula, 
= a + (n-1)d
here, is the last 4-digit number divisible by 5.
n is the number of 4-digit even numbers divisible by 5
d is the common difference between the numbers, which is 10 in this case
a is the first 4-digit number divisible by 5
9990 = 1000 + (n-1)*10
899 = n-1
n = 900
Hence, there are 900 4-digit even numbers divisible by 5
Answer:
√
28
Rewrite
28
as
2
2
⋅
7
.
Tap for more steps...
√
2
2
⋅
7
Pull terms out from under the radical.
2
√
7
The result can be shown in both exact and decimal forms.
Exact Form:
2
√
7
Decimal Form:
5.29150262
…
Step-by-step explanation:
Answer:
i guess it's the second one, 16x2+9y2, since they are both raised to 2 and they are binomial
Bring the 13 over to read
13-12y-13=0
then move the 12y over do it becomes
13-13=12y
0=12y
y=0
