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3 years ago

Will give the brains of me brains and my brains and maby ur brain to u how many brains can i give u if u ask this quetion right?

Mathematics

1 answer:

Mashcka [7]3 years ago

7 0

Answer:

2.4 bags

Step-by-step explanation:

Uh you can keep your brains.

Using the data table, we get:

1, 2, 2, 3, 4 as our data.

Finding the mean:

(1+2+2+3+4)÷5=

12÷5=

2.4 bags

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65 % of 60 is what number?

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Which number sentence is true? O A) 2.3 x 102 > 2000 OB) 3.45 > 1-4.35| OC) 345 > 5:33 825 OD 13

OLEGan [10]

Answer:

D) -2.14< root10 <|-2.8|

Step-by-step explanation:

the value for -2.14 is as plain as you can see, the negative version of 2.14.

The square root of 10 is 3.16227766.

The lines next to -2.8 is asking for the absolute value of -2.8, or the distance between that number and zero. The distance between -2.8 and 0 is positive 2.8, because distance can't be negative.

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3 years ago

A bag contains different colored candies. There are 50 candies in the bag, 28 are red, 10 are blue, 8 are green and 4 are yellow

Mrrafil [7]

Answer:

$\displaystyle \frac{54}{5405}$ .

Step-by-step explanation:

How many unique combinations are possible in total?

This question takes 5 objects randomly out of a bag of 50 objects. The order in which these objects come out doesn't matter. Therefore, the number of unique choices possible will the sames as the combination

$\displaystyle \left(50\atop 5\right) = 2,118,760$ .

How many out of that 2,118,760 combinations will satisfy the request?

Number of ways to choose 2 red candies out a batch of 28:

$\displaystyle \left( 28\atop 2\right) = 378$ .

Number of ways to choose 3 green candies out of a batch of 8:

$\displaystyle \left(8\atop 3\right)=56$ .

However, choosing two red candies out of a batch of 28 red candies does not influence the number of ways of choosing three green candies out of a batch of 8 green candies. The number of ways of choosing 2 red candies and 3 green candies will be the product of the two numbers of ways of choosing

$\displaystyle \left( 28\atop 2\right) \cdot \left(8\atop 3\right) = 378\times 56 = 21,168$ .

The probability that the 5 candies chosen out of the 50 contain 2 red and 3 green will be:

$\displaystyle \frac{21,168}{2,118,760} = \frac{54}{5405}$ .

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3 years ago

He sum of two numbers, x and y, is 12. the difference of x and two times y is 6. what are the values of x and y? x = 8, y = 4 x

Sveta_85 [38]

The last choice is correct

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2 years ago