Notice the grid, the points are (-5, -2) and (4, -1), thus
![\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\ \quad \\ \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ % (a,b) &&(~{{ 4}} &,&{{ -1}}~) % (c,d) &&(~{{ -5}} &,&{{ -2}}~) \end{array}~~ % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2} \\\\\\ d=\sqrt{[-5-4]^2+[-2-(-1)]^2}\implies d=\sqrt{(-5-4)^2+(-2+1)^2} \\\\\\ d=\sqrt{(-9)^2+(-1)^2}\implies d=\sqrt{81+1}\implies d=\sqrt{82}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%5C%5C%20%5Cquad%20%5C%5C%0A%5Cbegin%7Barray%7D%7Bccccccccc%7D%0A%26%26x_1%26%26y_1%26%26x_2%26%26y_2%5C%5C%0A%25%20%20%28a%2Cb%29%0A%26%26%28~%7B%7B%204%7D%7D%20%26%2C%26%7B%7B%20-1%7D%7D~%29%20%0A%25%20%20%28c%2Cd%29%0A%26%26%28~%7B%7B%20-5%7D%7D%20%26%2C%26%7B%7B%20-2%7D%7D~%29%0A%5Cend%7Barray%7D~~%0A%25%20%20distance%20value%0Ad%20%3D%20%5Csqrt%7B%28%7B%7B%20x_2%7D%7D-%7B%7B%20x_1%7D%7D%29%5E2%20%2B%20%28%7B%7B%20y_2%7D%7D-%7B%7B%20y_1%7D%7D%29%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0Ad%3D%5Csqrt%7B%5B-5-4%5D%5E2%2B%5B-2-%28-1%29%5D%5E2%7D%5Cimplies%20d%3D%5Csqrt%7B%28-5-4%29%5E2%2B%28-2%2B1%29%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0Ad%3D%5Csqrt%7B%28-9%29%5E2%2B%28-1%29%5E2%7D%5Cimplies%20d%3D%5Csqrt%7B81%2B1%7D%5Cimplies%20d%3D%5Csqrt%7B82%7D)
1. Find the surface area of the rectangular prism. (1 point)
<span>Measures are 2, 3, and 4 inches. Let W=2, L=3, H=4 </span>
<span>a rectangular has six sides, the total surface area is equal to 6 plains: </span>
<span>2*W*L + 2*L*H + 2*L*W </span>
<span>= 2*(W*L + L*H + L*W) </span>
<span>= 2 * (2*3 + 3*4 + 4*2) </span>
<span>= 2 * ( 6 + 12 + 8 ) </span>
<span>= 2 * 26 </span>
<span>= 52 ................... the last choice </span>
<span>2. A cube has a side length of x feet. Which expression represents the surface area of the cube? (1 point) </span>
<span>Area of one face = x^2, Total Area of 6 faces = 6*x^2 = 2x^2 units </span>
<span>3. Find the surface area of the cylinder. Use 3.14 for pi . (1 point) </span>
<span>Length: 15 cm, Diameter: 2 cm </span>
<span>A cylinder has 3 surfaces: two circles + one curved surface area </span>
<span>...... two circles of 2cm diameter (1cm radius) </span>
<span>A = pi*r^2 = 3.14*1*1 = 3.14 sq. cm ...... two circles' area = 6.28 sq.cm </span>
<span>Curved surface area = circumference * length </span>
<span>.... circumference = pi*d = 3.14 * 2 = 6.28 cm ......... length = 15 </span>
<span>curved surface area = 6.28*15 = 94.2 sq. cm </span>
<span>Add both for total surface area = 6.28 + 94.2 = 100.48 sq.cm </span>
<span>4. The bottom of a shopping bag measures 8 inches by 10 inches. The bag has a height of 12 inches. How much paper is needed to make the bag? (1 point) </span>
<span>two pieces of paper ... one for bottom = 8*10 = 80 sq.in </span>
<span>the other ... height * perimeter of the bottom = 12*(2*(10+8)) = 12 * 2 * 18 = 432 sq.in </span>
<span>Add both: 80 + 432 = 512 sq.in <<<<<<<<<<<</span>
Answer:
D. Bring a loan to an end.
Step-by-step explanation:
An amortized loan is a loan with scheduled payment plan which covers both the principal and interest, the interest expense for the period is paid first before the remainder of the payment reduces the principal. It is a way of brining a loan to an end.
Answer:16
Step-by-step explanation:
10÷5/8=16
