Divide the perimeter by 2, this will give you the sum of one length and one width.
68/2 = 34 yards
Now the length is 10 yards more, so subtract 10 from the 34 and divide by 2 again:
34 - 10 = 24
24 /2 = 12
The width is 12 yards.
The length is 12 + 10 = 22 yards.
Answer:
At (-2,0) gradient is -4 ; At (2,0) gradient is 4
Step-by-step explanation:
For this problem, we simply need to take the derivative of the function and evaluate when y = 0 (when crossing the x-axis).
y = x^2 - 4
y' = 2x
The function y = x^2 - 4 cross the x-axis when:
y = x^2 - 4
0 = x^2 - 4
4 = x^2
2 +/- = x
Hence, this curve crosses the x-axis twice, once at (-2,0) and again at (2,0).
The gradient at these points are as follows:
y' = 2(-2) = -4
y' = 2(2) = 4
Cheers.
The answer is 30°.
Rule: All three sides must add up to 180°.
Since A=60 and the side vertical to the angle which is 90° then side C would be C=90° and that adds up to 150°, so you can conclude that angle B is 30°.
I hope I helped!
Answer:
$378,000
Step-by-step explanation:
The computation of the bad debt expense for the year is shown below:
Bad debt expense = Outstanding account receivable × estimated percentage given - credit balance of allowance for doubtful account
= $6,500,000 × 0.06 - $12,000
= $390,000 - $12,000
= $378,000
We simply deduct the credit balance from the estimated balance so that the correct amount could arrive
Answer:
C. Test for Goodness-of-fit.
Step-by-step explanation:
C. Test for Goodness-of-fit would be most appropriate for the given situation.
A. Test Of Homogeneity.
The value of q is large when the sample variances differ greatly and is zero when all variances are zero . Sample variances do not differ greatly in the given question.
B. Test for Independence.
The chi square is used to test the hypothesis about the independence of two variables each of which is classified into number of attributes. They are not classified into attributes.
C. Test for Goodness-of-fit.
The chi square test is applicable when the cell probabilities depend upon unknown parameters provided that the unknown parameters are replaced with their estimates and provided that one degree of freedom is deducted for each parameter estimated.
