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Reil [10]
3 years ago
11

What is the range of the function f(x) = 4x + 9, given the domain D = {-4, -2, 0, 2}?

Mathematics
1 answer:
AysviL [449]3 years ago
8 0

Answer:

Hello :

Answer :C

Because :

f ( - 4 ) = 4(-4)+9 = -16 +9 = -7

f ( - 2 ) = 4(-2)+9 = - 8 +9 = 1

f (0 ) = 4(0)+9 = 9

f ( 2 ) = 4(2)+9 = 17

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F(x)=−7x−1 <br> f(____)= -8
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-8 = -7x-1
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7 0
3 years ago
7 apples cost 4.55 dollars how much do 9 apples cost
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Determine the volume of the parallelepiped with one vertex at the origin and the three vertices adjacent to it at (2, â1, â1), (
valentinak56 [21]

Answer:

23

Step-by-step explanation:

Here is the complete question

Find the volume of the parallelepiped with one vertex at the origin and adjacent vertices at (1, 0, -3), (1, 2, 4), and (5, 1, 0).

Solution

We find the volume of the parallelepiped by making a 3 × 3 column matrix whose columns are the corresponding coordinates of the vertices of the parallelepiped.

So, (1, 0, -3), (1, 2, 4)  and (5, 1, 0)

A = \left[\begin{array}{ccc}1&1&5\\0&2&1\\-3&4&0\end{array}\right]

The determinant of A is the volume of the parallelepiped. So,

detA = 1(2 × 0 - 4 × 1) - 1(0 × 0 - (-3) × 1) + 5(0 × 4 - (-3) × 2)

= 1(0 - 4) - 1(0 + 3) + 5(0 + 6)

= 1(-4) - 1(3) + 5(6)

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= 23

So the volume of the parallelepiped is 23

4 0
2 years ago
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