Answer:
...................It is true
<span>Dr. Kluivert makes the suggestion because Ike meets the diagnostic criteria for depression and has exhibited symptoms such as a disinterest in his favorite activities, a lack of appetite, an inability to sleep, difficulty concentrating, and a feeling of exhaustion that doesn't decrease even with rest.</span>
Arkansas, Missouri, Iowa, Oklahoma, Kansas and Nebraska. I am pretty sure those are them. Sorry if i'm wrong
Answer: B) free association
Explanation:
Free association is used during therapy to identify what a person is thinking without conscious assessment, thereby removing all barriers to their thoughts and feelings. In this example, Carolyn's therapist can understand what Carolyn is thinking without any suggestions from the therapist or any censorship from Carolyn.
This technique was developed by Sigmund Freud in the 1890s as a method to replace hypnosis.
Answer:

Explanation:
Your question has one part only: <em>a) The average weight of the eggs produced by the young hens is 50.1 grams, and only 25% of their eggs exceed the desired minimum weight. If a Normal model is appropriate, what would the standard deviation of the egg weights be?</em>
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<h2><em>Solution</em></h2><h2><em /></h2>
You are given the <em>mean</em>, the reference value, and the <em>percent of egss that exceeds that minimum</em>.
In terms of the parameters of a normal distribution that is:
- <em>mean</em> =<em> 50.1g</em> (μ)
- Area of the graph above X = 51 g = <em>25%</em>
Using a standard<em> normal distribution</em> table, you can find the Z-score for which the area under the curve is greater than 25%, i.e. 0.25
The tables with two decimals for the Z-score show probability 0.2514 for Z-score of 0.67 and probabilidad 0.2483 for Z-score = 0.68.
Thus, you must interpolate. Since, (0.2514 + 0.2483)/2 ≈ 0.25, your Z-score is in the middle.
That is, Z-score = (0.67 + 0.68)/2 = 0.675.
Now use the formula for Z-score and solve for the <em>standard deviation</em> (σ):


