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Elza [17]
3 years ago
6

Cost to store= $162 markup= 40%

Mathematics
1 answer:
Komok [63]3 years ago
6 0
162 × 1.40

new price = 226.8
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Help me solve (b) in this quadrilateral
Savatey [412]

Answer:

b = 87°

Step-by-step explanation:

In order to answer this question, we need to utilise an important angle fact which is <em>angles in a quadrilateral add up to 360° </em>

Using the information we can set up an equation to find the value of b

→ Form equation

63 + 140 + 70 + b = 360

→ Simplify

273 + b = 360

→ Minus 273 from both sides isolate b

b = 87°

3 0
3 years ago
Read 2 more answers
Justin is marking a border for a garden. He walks 200 feet to the east, then turns and
ELEN [110]

Answer:

d = 233.23 feet

Step-by-step explanation:

Given that,

Justin walks 200 feet to the east, then turns and  walks 120 feet due south.

We need to find the total distance walked by Justin. Let the distance be d.

We can use the Pythagoras theorem to find it such that,

d=\sqrt{d_1^2+d_2^2} \\\\d=\sqrt{200^2+120^2} \\\\d=233.24\ feet

So, he walk 233.23 feet in all.

3 0
2 years ago
What is the measure of DG?
Masja [62]

Answer:

170

Step-by-step explanation:

7 0
3 years ago
Round the number 13.734 to the nearest whole<br>number (positive integer).​
loris [4]
Answer: 14
The number to the right of the decimal point is either 5 or greater than that, so the 13 is increased by 1 which results in 14.
3 0
3 years ago
Plz hurry!!!! thank you!!!!
Nikitich [7]

Answer:

Area of trapezium = 4.4132 R²

Step-by-step explanation:

Given, MNPK is a trapezoid

MN = PK and ∠NMK = 65°

OT = R.

⇒ ∠PKM = 65° and also ∠MNP = ∠KPN = x (say).

Now, sum of interior angles in a quadrilateral of 4 sides = 360°.

⇒ x + x + 65° + 65° = 360°

⇒ x = 115°.

Here, NS is a tangent to the circle and ∠NSO = 90°

consider triangle NOS;

line joining O and N bisects the angle ∠MNP

⇒ ∠ONS = \frac{115}{2} = 57.5°

Now, tan(57.5°) = \frac{OS}{SN}

⇒ 1.5697 = \frac{R}{SN}

⇒ SN = 0.637 R

⇒ NP = 2×SN = 2× 0.637 R = 1.274 R

Now, draw a line parallel to ST from N to line MK

let the intersection point be Q.

⇒ NQ = 2R

Consider triangle NQM,

tan(∠NMQ) = \frac{NQ}{QM}

⇒ tan65° = \frac{NQ}{QM}

⇒ QM = \frac{2R}{2.1445}

QM = 0.9326 R .

⇒ MT = MQ + QT

          = 0.9326 R + 0.637 R  (as QT = SN)

⇒ MT = 1.5696 R

⇒ MK = 2×MT = 2×1.5696 R = 3.1392 R

Now, area of trapezium is (sum of parallel sides/ 2)×(distance between them).

⇒ A = (\frac{NP + MK}{2}) × (ST)

       = (\frac{1.274 R + 3.1392 R}{2}) × 2 R

       = 4.4132 R²

⇒ Area of trapezium = 4.4132 R²

5 0
3 years ago
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