Answer:
Answer: The correct option is (D) P″(9, -12) and Q″(15, -3).
Step-by-step explanation: Given that triangle PQR is dilated by a scale factor of 1.5 to form triangle P′Q′R′. This triangle is then dilated by a scale factor of 2 to form triangle P″Q″R″.
The co-ordinates of vertices P and Q are (3, -4) and (5, -1) respectively.
We are to find the co-ordinates of the vertices P″ and Q″.
Case I : ΔPQR dilated to ΔP'Q'R'
The co-ordinates of P' and Q' are given by
Case II : ΔP'Q'R' dilated to ΔP''Q''R''
The co-ordinates of P'' and Q'' are given by
Thus, the co-ordinates of the vertices P'' and Q'' are (9, -12) and (15, -3).
Option (D) is CORRECT.
Step-by-step explanation:
Solve for
x
x
by simplifying both sides of the equation, then isolating the variable.
x
=
−3
Z^2 - 2z - 35 = 0
(z - 7)(z + 5) = 0
z - 7 = 0
z = 7
z + 5 = 0
z = -5
solution is : z = 7,-5
Given :
An airplane flying at an altitude of 2600 m is approaching an airport run away located 56 km away.
To Find :
The airplane’s angle of decent.
Solution :
Height of plane, h = 2600 m.
Horizontal distance of airplane from vertices is, d = 56 km = 56000 m.
Let, angle of depression is Ф.
So,
Therefore, the angle of decent is 87.34°.
Hence, this is the required solution.
Answer:
bam
Step-by-step explanation:
bam
