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s344n2d4d5 [400]
2 years ago
13

Lenmana started studying how the number of branches on her tree grows over time. The number of branches increases by a factor of

11/6 every 3.5 years, and can be modeled by a function, N, which depends on the amount of time, t (in years).
When Lenmana began the study, her tree had 48 branches.

Write a function that models the number of branches t years since Lenmana began studying her tree.

N(t)=
Mathematics
1 answer:
Ad libitum [116K]2 years ago
7 0

Answer:

N(t) = 48 * 11/6^{\frac{t}{3.5} }

Step-by-step explanation:

The formula for <u>exponential growth</u> is y = ab^x.

To write this equation, we know it has to start with 48 (which is the variable a). We need to add the rate of growth. This is 11/6 (which is variable b). But we also need to account for the "every 3.5 years" part, so divide the x as an exponent by 3.5.

N(t) = 48 * 11/6^(t/3.5)

This equation is easy to test, and it's a good idea to test it after you write it. For example, after 3.5 years we know that it should have 48*11/6 branches. Does our equation work? Yes.

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Answer:

c, d and e

Step-by-step explanation:

A linear expression is an expression in which sum of exponents of variables is at most 1 in each of its terms.

Option a: 3x - 2

Here, the exponent of the variable is 1.

So, it is a linear expression.

Option b: -9y

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Option c: -7x^2 + 4x

Here, the highest exponent of the variable is 2.

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Option d: -\frac{1}{2} x^2

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So, it is NOT a linear expression.

Option e: 8xy

Here, sum of exponents of variables is 2.

So, it is NOT a linear expression.

Hence, c, d and e are NOT algebraic expressions.

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