Answer:
Let two consecutive multiples of 3 be x and (x+3)
A/q,
x * (x+3) = 648
➡ x² + 3x = 648
➡ x² + 3x -648 = 0
➡ x² + 27x - 24x -648 = 0
➡ x ( x + 27 ) -24 ( x +27)
➡ ( x - 24) ( x + 27)
➡ x = 24 and x = -27
so, we take x = 24.
Required multiples of 3
➡ x = 24
➡ x +3 = 24+3 = 27.
34% is the correct answer
Answer: A
2x^2+2x-8 is the quotient when x+3 divides P(x)
=> P(x) = (2x² + 2x -8)(x + 3) = 2(x² + x - 4)(x + 3) = (x² + x - 4) (2x + 6)
=> the quotient when 2x+6 divides p(x) is x² + x - 4
Step-by-step explanation:
Answer:
Y = 50
Step-by-step explanation:
Solve for Y:
Y - 9 = 41
Add 9 to both sides:
Y + (9 - 9) = 9 + 41
9 - 9 = 0:
Y = 41 + 9
41 + 9 = 50:
Answer: Y = 50
Answer:
60
Step-by-step explanation:
