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Alex777 [14]
3 years ago
12

Find x, the slant height of the pyramid shown, to the nearest tenth.

Mathematics
2 answers:
IRISSAK [1]3 years ago
8 0

I just did this question and 5 mm is not the answer the actual answer is (D. 4.3 mm) Because when I looked back it said 5 mm isn't the answer so this is what I'm gonna leave here. that dude below has the wrong answer.


pychu [463]3 years ago
4 0
There is a right triangle with the height (4) and half the base (3) as legs and the slant height (x) is the hypotenuse:
4² + 3²= x²
x² = 16+9
x =5 mm
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Solve the inequality. Check your solutions.
Komok [63]
The inequality is 

7- \frac{2}{b}\ \textless \ \frac{5}{b}

write 7 as 7b/b to have all the expressions in common denominator:

\frac{7b}{b} - \frac{2}{b}\ \textless \ \frac{5}{b}

\frac{7b-2}{b} \ \textless \ \frac{5}{b}

\frac{7b-2}{b}- \frac{5}{b}\ \textless \ 0

\frac{7b-2-5}{b}\ \textless \ 0

\frac{7b-7}{b}\ \textless \ 0

\frac{7(b-1)}{b}\ \textless \ 0

here b=1 is a root and b=0 is not in the domain of the expression, but it still has an effect in the sign of the expression.

the sign table of \frac{7(b-1)}{b} is :

+++++++[0] --------[1] +++++

this means that for values of b to the left of 0 and to the right of 1, the expression is positive, and for values of b in (0, 1), the expression is negative.

that is \frac{7(b-1)}{b}\ \textless \ 0 for b∈(0, 1)

Answer: (0, 1)
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4 years ago
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Answer:

496

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