Answer:
A.
mean = 724.2
Median = 715
Mode = 768
B.
Range = 85
Standard deviation = 29.30
C.
Interval = [665.6, 782.8]
Step-by-step explanation:
Number of samples n = 25
Summation X= 769 + 691 + 699 +730+711+ 765+ 702 718 +719 +712+ 768 +688 +757+695 768 +735 +709 +758 +708+ 693 +736 700+ 687 +772 +715 = 18105
A.
1. Mean = 18105/25
= 724.2
2. Median is the middle value when arranged from the least value to the highest = 715
3. Mode is the number with the highest frequency = 768 (occured two times)
B.
1. Range = highest value - lowest value
Highest value = 772
Lowest value = 687
772-687 = 85
2. Standard deviation = √(X-barX)²/n-1
= √20604/25-1
=√858.5
= 29.30
Please check attachment for the full calculation of the standard deviation
C.
Interval
[Mean - 2(sd), mean + 2(sd)]
= [724.2-2x29.3, 724.2+2x29.3]
=[665.6, 782.8]
Answer:
![BC=4\ units](https://tex.z-dn.net/?f=BC%3D4%5C%20units)
Step-by-step explanation:
The picture of the question in the attached figure
we know that
----> by SOH (opposite side divided by the hypotenuse)
we have
![AB=8\ units\\\\sin(30^o)=\frac{1}{2}](https://tex.z-dn.net/?f=AB%3D8%5C%20units%5C%5C%5C%5Csin%2830%5Eo%29%3D%5Cfrac%7B1%7D%7B2%7D)
solve for BC
![BC=sin(30^o)(AB)](https://tex.z-dn.net/?f=BC%3Dsin%2830%5Eo%29%28AB%29)
substitute the values
![BC=(\frac{1}{2})(8)](https://tex.z-dn.net/?f=BC%3D%28%5Cfrac%7B1%7D%7B2%7D%29%288%29)
![BC=4\ units](https://tex.z-dn.net/?f=BC%3D4%5C%20units)
Answer:
P(Z < 2.37) = 0.9911.
Step-by-step explanation:
We are given that Let z denote a random variable that has a standard normal distribution.
Let Z = a random variable
So, Z ~ Standard Normal(0, 1)
As we know that the standard normal distribution has a mean of 0 and variance equal to 1.
Z =
~ N(0,1)
where,
= mean = 0
= standard deviation = 1
Now, the probability that z has a value less than 2.37 is given by = P(Z < 2.37)
P(Z < 2.37) = P(Z <
) = P(Z < 2.37) = 0.9911
The above probability is calculated by looking at the value of x = 2.37 in the z table which has an area of 0.9911.
To find the experimental probability, you will add the outcomes that resulted in even number and make that a ratio to the total number of outcomes.
<u>(12 + 14 + 18)</u>
(13 + 12 + 12 +14 + 11 + 18)
44/80 = 0.55
0.55 = 55%
The answer is choice D.