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pickupchik [31]
2 years ago
14

For a given wave if the frequency doubles the wave length?

Physics
1 answer:
pav-90 [236]2 years ago
5 0
For a given wave in a given medium, if the frequency doubles,
the wavelength becomes 50% shorter.

That is, it becomes half as long as it was originally.
You might be interested in
An atom of a certain element has 36 protons, 36 electrons, and a mass number of 84. At room temperature, this element is a very
Grace [21]

Answer:

12 neutrons

Explanation:

The number of protons also shows the atomic number. Therefore the element in question is Krypton (Kr), which also is a noble gas.

Neutrons = Mass number - protons - electrons

Here neutrons = 84 - 36 - 36 = 12

5 0
3 years ago
Calculate the gravitational potential energy of a 2 kg banana hanging 5
Hunter-Best [27]

Answer:

  100 J

Explanation:

The potential energy is given by the formula ...

  PE = mgh

  = (2 kg)(10 m/s^2)(5 m) = 100 J

7 0
3 years ago
Steam enters a counterflow heat exchanger operating at steady state at 0.07 MPa with a specific enthalpy of 2431.6 kJ/kg and exi
PIT_PIT [208]

Answer:

Explanation:

Given:

Steam Mass rate, ms = 1.5 kg/min

= 1.5 kg/min × 1 min/60 sec

= 0.025 kg/s

Air Mass rate, ma = 100 kg/min

= 100 kg/min × 1 min/60 sec

= 1.67 kg/s

A.

Extracting the specific enthalpy and temperature values from property table of “Saturated water – Pressure table” which corresponds to temperature at 0.07 MPa.

xf, quality = 0.9.

Tsat = 89.9°C

hf = 376.57 kJ/kg

hfg = 2283.38 kJ/kg

Using the equation for specific enthalpy,

hi = hf + (hfg × xf)

= 376.57 + (2283.38 × 0.9)

= 2431.552 kJ/kg

The specific enthalpy of the outlet, h2 = hf

= 376.57 kJ/kg

B.

Rate of enthalpy (heat exchange), Q = mass rate, ms × change in specific enthalpy

= ms × (hi - h2)

= 0.025 × (2431.552 - 376.57)

= 0.025 × 2055.042

= 51.37455 kW

= 51.38 kW.

5 0
2 years ago
What is the magnification of an object that is 4.15 m in front of a camera that has an image position of 5.0 cm?
Stolb23 [73]
-0.012

Done !!!!!!!!
4 0
3 years ago
Describe the evolution of a pulsar over time, in particular how the rotation and pulse signal changes over time.
madam [21]

Answer:

As beams of particles and their associated energy are given off, the pulsar will lose energy slowly, which will decrease the rate of its rotation. The frequency of pulses would therefore decrease, so that fewer pulses are observed in a given time span. The strength of the pulse signal will also decrease so the pulses will become fainter. Eventually, the pulsar should rotate so slowly and have such a low emission of radiation that it would no longer be observable.

3 0
3 years ago
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