Ask question

Ask question

All categories

2 years ago

15

The objects shown in the following diagrams have different masses and are different distances apart. Which diagram shows the two

objects that have the greatest force of gravity acting between them?

1 answer:

sergiy2304 [10]2 years ago

5 0

Answer:

C. 10kg to 10kg

Explanation:

You have to picture to it I think

You might be interested in

1 The Earth's crust is made up of plates that can move. Which of the following topographic features could be directly formed by

olga_2 [115]

Can you write this better and from my info of what i know i know that one way is the trenches in the ocean like marianas trench <span />

7 0

3 years ago

A roller coaster track is 3000 meters long. It takes 100 seconds to travel once around the roller coaster. What is the average s

Svetllana [295]

All you have to do is divide 3000 by 100, Its 30

6 0

3 years ago

Read 2 more answers

lanet R47A is a spherical planet where the gravitational acceleration on the surface is 3.45 m/s2. A satellite orbitsPlanet R47A

qaws [65]

$2.6×10^6\:\text{m}$

Explanation:

The acceleration due to gravity g is defined as

$g = G\dfrac{M}{R^2}$

and solving for R, we find that

$R = \sqrt{\dfrac{GM}{g}}\:\:\:\:\:\:\:(1)$

We need the mass M of the planet first and we can do that by noting that the centripetal acceleration $F_c$ experienced by the satellite is equal to the gravitational force $F_G$ or

$F_c = F_G \Rightarrow m\dfrac{v^2}{r} = G\dfrac{mM}{r^2}\:\:\:\:\:(2)$

The orbital velocity <em>v</em> is the velocity of the satellite around the planet defined as

$v = \dfrac{2\pi r}{T}$

where <em>r</em><em> </em>is the radius of the satellite's orbit in meters and <em>T</em> is the period or the time it takes for the satellite to circle the planet in seconds. We can then rewrite Eqn(2) as

$\dfrac{4\pi^2 r}{T^2} = G\dfrac{M}{r^2}$

Solving for <em>M</em>, we get

$M = \dfrac{4\pi^2 r^3}{GT^2}$

Putting this expression back into Eqn(1), we get

$R = \sqrt{\dfrac{G}{g}\left(\dfrac{4\pi^2 r^3}{GT^2}\right)}$

$\:\:\:\:=\dfrac{2\pi}{T}\sqrt{\dfrac{r^3}{g}}$

$\:\:\:\:=\dfrac{2\pi}{(1.44×10^4\:\text{s})}\sqrt{\dfrac{(5×10^6\:\text{m})^3}{(3.45\:\text{m/s}^2)}}$

$\:\:\:\:= 2.6×10^6\:\text{m}$

5 0

3 years ago

As sound waves move from air to glass, the wave property of ________ will cause the wave to bend in that direction

Zarrin [17]

<span>The amplitude because that controls the height of the wave. Correct answer: Amplitude.</span>

5 0

3 years ago

If an object has 180 J of PE and a mass of .5kg, what is its height?

Nonamiya [84]

PE=mgh
180=0.5*10*h
180=5h
h=180/5=36 m

7 0

3 years ago