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3 years ago

What is the momentum of a 3.5-kilogram object moving with a velocity of 6 m/s east?

Physics

1 answer:

Ghella [55]3 years ago

3 0

Momentum formula - P=MV
P=MV
P= (3.5 kg)(6 m/s) - multiply
P= 21 kg x m/s to the east
Hope this helps

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What is the difference between sounds that have the same pitch and loudness?

amm1812

Answer:

Option C

Sound quality

Explanation:

Sounds with the same pitch and loudness means they share natural frequency where frequency here implies the the number of vibrations that an individual particle makes per unit time (seconds). Additionally, when the pitch and loudness are the sane, the resonance and standing waves of these sounds will be similar. However, the quality of the sounds will vary. Therefore, option C is the correct one.

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3 years ago

A river flows with a speed of 0.600 m/s. A student first swims upriver 0.500 km, then turns around and returns to his starting p

DerKrebs [107]

Answer:

a) 1111.0 seconds

b) 833.3 s

c) Because of proportions

Explanation:

a) Total time of round trip is the sum of time upriver and time downriver

$t_{total}=t_{up}+t_{down}$

Time upriver is calculated with the net speed of student and 0.500 km:

$t_{up}=\frac{d_{istance}}{|v_{swimmer}|} ;\\v_{swimmer}=v_{relative to river}+v_{river}=-1.2+0.6=-0.6 m/s\\t_{up}=\frac{500 m}{0.6 m/s}=833.3 s$

(Becareful with units 0.5 km= 500m) Similarly of downriver:

$t_{down}=\frac{d_{istance}}{|v_{swimmer}|} ;\\v_{swimmer}=1.2+0.6=1.8 m/s\\t_{down}=\frac{500 m}{1.8 m/s}=277.7 s$

So the sum is:

$t_{total}=1111.0s$

b) Still water does not affect student speed, so total time would be simply:

$t_{total}=\frac{1000 m}{1.2 m/s}=833.3 s$

c) For the upriver trip, student moved half the distance in half speed of the calculation in b), so it kept the same ratio and therefore, same time. So the aditional time is actually the downriver.

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3 years ago

earnstyle [38]

Answer:

0.0312J

Explanation:

Let x be the distance the staple moves:

$x=0.150m-0.115m=0.035m$

And spring constant is $k=51.0N/m$

$PE=0.5kx^2\\=0.5\times 51.0\times 0.035^2\\\\=0.312$

Hence, the potential energy is 0.0312J

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3 years ago