What is the momentum of a 3.5-kilogram object moving with a velocity of 6 m/s east?
1 answer:
You might be interested in
Consider the east-west direction along x-axis and north-south direction along y-axis. In unit vector notation, velocities can be given as
= velocity of car A before collision = 0 i -
j
= velocity of car B before collision =
i + 0 j
= velocity of combination after collision = (35.8 Cos31.6) i - (35.8 Sin31.6) j = 30.5 i - 18.8 j
= mass of car A = 1750 kg
= mass of car B = 1450 kg
Using conservation of momentum
+
= (
+
) (
)
(1750) (0 i - j) + (1450) (
i + 0 j) = (1750 + 1450) (30.5 i - 18.8 j)
(1450) i - (1750)
j = 97600 i - 60160 j
Comparing the coefficient of "i" and "j" both side
(1450) = 97600 and - (1750)
= - 60160
= 67.3 km/h and
= 34.4 km/
Answer:
0.758 N
Explanation:
mass of ball, = 36 g = 0.036 kg
radius, r = 19 cm = 0.19 m
tangential velocity, v = 200 cm / s = 2 m /s
The tension is the string is equal to the centripetal force acting on the ball.
The centripetal force acting on the ball is given by
T = 0.758 N
Thus, the tension in the string is given by 0.758 N.