Answer:
Tangential
Explanation: This is a kind of force which act on a moving body in such a way that it is curved in the direction of the path of the body. This implies that when the velocity of the object is positive, the acceleration will be negative.
Use conservation of momentum ;
m1u1 + m2u2 = m1v1 + m2v2
1200×15.6 + 0 = 2700v
v = 18720/2700
v = 6.933 or ~ 7 m/s
Answer:
The magnetic field is 
Explanation:
From the question we are told that
The mass of the metal rod is 
The current on the rod is 
The distance of separation(equivalent to length of the rod ) is 
The coefficient of kinetic friction is 
The kinetic frictional force is 
The constant speed is 
Generally the magnetic force on the rod is mathematically represented as
For the rod to move with a constant velocity the magnetic force must be equal to the kinetic frictional force so
=> 
=> 
=>
<span>32 mph
First, let's calculate the location of the particle at t=1, and t=4
t=1
s = 6*t^2 + 2*t
s = 6*1^2 + 2*1
s = 6 + 2
s = 8
t = 4
s = 6*t^2 + 2*t
s = 6*4^2 + 2*4
s = 6*16 + 8
s = 96 + 8
s = 104
So the particle moved from 8 to 104 over the time period of 1 to 4 hours. And the average velocity is simply the distance moved over the time spent. So:
avg_vel = (104-8)/(4-1) = 96/3 = 32
And since the units were miles and hours, that means that the average speed of the particle over the interval [1,4] was 32 miles/hour, or 32 mph.</span>
Answer:
The magnetic flux density is 3 x 10⁵ Wb/m²
Explanation:
Given;
magnetic flux of each line of force, Ф = 30 Wb
area of the bar magnet, A = 1 cm² = 1 x 10⁻⁴ m²
The flux density of the magnet is the measure of the concentration of the magnetic flux per unit area. The unit is Wb/m² or Tesla.
B = Ф / A
B = 30 / (1 x 10⁻⁴ )
B = 3 x 10⁵ Wb/m²
Therefore, the magnetic flux density is 3 x 10⁵ Wb/m²
