1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ivolga24 [154]
1 year ago
5

An object is located 70 cm from a concave mirror with a focal length of 15 cm. What is the image

Physics
1 answer:
Stels [109]1 year ago
5 0

(a) The distance of the image formed by the concave mirror is 19.1 cm.

(b) The image formed is diminished and real.

<h3>Image distance </h3>

The distance of the image formed by the concave mirror is calculated as follows;

1/f = 1/v + 1/u

1/v = 1/f - 1/u

1/v = 1/15 - 1/70

1/v = 0.05238

v = 1/0.05238

v = 19.1 cm

The image distance is smaller than object distance, thus the image formed is diminished and real.

Learn more about concave mirror here: brainly.com/question/13164847

#SPJ1

You might be interested in
An object of mass 2kg raised to a height 10m possess potential energy of 200J. What is the kinetic energy and potential energy a
Shtirlitz [24]

Explanation:

{\bold{\sf{\underline{Understanding \: the \: concept}}}}

✠ This question says that there is an object and its mass is 2 kg ; it's raised to a height 10 m and possess potential energy of 200 J. Now this question ask us to find the kinetic energy and the potential energy at a height 4 metre.

\bold{↬{   }}{\bold{\sf{\underline{Given \: that}}}}

✰ Mass = 2 kilograms

✰ Raised height = 10 metres

✰ Posses potential energy = 200 Joules

\bold{↬{   }}{\bold{\sf{\underline{To \: find}}}}

✰ Kinetic energy at a height 4 metre

✰ Potential energy at a height 4 metre

{\bold{\sf{\underline{Solution}}}}

✰ Kinetic energy at a height 4 metre = 120 J

✰ Potential energy at a height 4 metre = 80 J

{\bold{\sf{\underline{Using \: concepts}}}}

✰ Potential energy formula.

{\bold{\sf{\underline{Using \: formula}}}}

✰ Potential energy = mgh

{\bold{\sf{\underline{We \: also \: write \: these \: as}}}}

✰ Potential energy as P.E

✰ Mass as m

✰ Joules as J

✰ Height as h

✰ Raised height as g

{\bold{\sf{\underline{Full \: solution}}}}

<h3>✠ Let us find the Potential energy.</h3>

↦ Potential energy = mgh

↦ Potential energy = 2 × 10 × 4

↦ Potential energy = 20 × 4

↦ Potential energy = 80 J

<h3>✠ Now according to the question let us find the kinetic energy</h3>

↦ Kinetic energy = Posses potential energy - Finded potential energy

↦ Kinetic energy = 200 J - 80 J

↦ Kinetic energy = 120 Joules

4 0
3 years ago
Read 2 more answers
In the picture below, label which particle is the solute and which is the solvent ​
klasskru [66]
The black circles are the solvent and the open circles are the solute
8 0
2 years ago
The mass of Jupiter is 1.9 × 1027 and that of the sun is 1.99 × 1030. The
n200080 [17]

Answer:

F = 4.147 × 10^23

v = 1.31 × 10^4

Explanation:

Given the following :

mass of Jupiter (m1) = 1.9 × 10^27

Mass of sun (m2) = 1.99 × 10^30

Distance between sun and jupiter (r) = 7.8 × 10^11m

Gravitational force (F) :

(Gm1m2) / r^2

Where ; G = 6.673×10^-11 ( Gravitational constant)

F = [(6.673×10^-11) × (1.9 × 10^27) × (1.99 × 10^30)] / (7.8 × 10^11)^2

F = [25.231 × 10^(-11+27+30)] / (60.84 × 10^22)

F = (25.231 × 10^46) / (60.84 × 10^22)

F = 3.235 × 10^(46 - 22)

F = 0.4147 × 10^24

F = 4.147 × 10^23

Speed of Jupiter (v) :

v = √(Fr) / m1

v = √[(4.147 × 10^23) × (7.8 × 10^11) / (1.9 × 10^27)

v = √32.3466 × 10^(23+11) / 1.9 × 10^27

v = √32.3466× 10^34 / 1.9 × 10^27

v = √17. 023 × 10^34-27

v = √17.023 × 10^7

v = 13047.221

v = 1.31 × 10^4

4 0
3 years ago
An 800 kHz radio signal is detected at a point 3.2 km distant from a transmitter tower. The electric field amplitude of the sign
hammer [34]

Answer:

1.07 nT

Explanation:

We know that E/B = c where E = electric field amplitude = 320 mV/m = 0.32 V/m, B = magnetic field amplitude and c = speed of light = 3 × 10⁸ m/s.

So, B = E/c

Substituting E and c into B, we have

B = E/c

= 0.32 V/m ÷ 3 × 10⁸ m/s

= 0.1067 × 10⁻⁸ T

= 1.067 × 10⁻⁹ T

= 1.067 nT

≅ 1.07 nT

3 0
3 years ago
A very long, uniformly charged cylinder has radius R and linear charge density λ. Find the cylinder's electric field strength ou
mixer [17]

The cylinder's electric field magnitude, at a distance <em>r</em> from the axis of the cylinder (greater than the cylinder's radius), is equal to E= \frac{\lambda}{2\pi \epsilon_0 \cdot r}

<h3>Further explanation</h3>

Matter is the building block of everything that we encounter in our lives. Matter is made of atoms, which are in turn made of tiny particles which are called electrons, protons, and neutrons. The ammount of these 3 elements, and their topological configuration in the atoms, is what determines what a certain element is (like Carbon, Hydrogen, Iron, etc).

In some cases, some elements may lose or gain some electrons. Regarded that this missing or extra electrons are not very high in number, the material doesn't lose any of its properties, however it will always try to get its number of electrons back to normal. This is when we say that an element has a <em>charge</em>, which is a measure of how much electrons a body needs to get back to normal. A body has positive charge if it lacks electrons, and has negative charge if it has extra electrons.

This charge causes the material to have an Electric field, which is a measure of how much does it attract or repel electrons. In the case of our problem, we need to compute exactly that, the Electric field. In our problem, we have an infinitely long cylinder with a linear charge density \lambda, this means that all parts of the cylinder have the same charge, and due to symmetry, the electric field is constant on the angular and longitudinal directions of the cylinder.

This makes easy to apply Gauss' Law, since for a Gaussian curve in the shape of a concentric cylinder (with a higher radius than that of our charged cylinder) we can write:

\Phi = \frac{\lambda \cdot L}{\epsilon_0}

Where \Phi is called the Electric flux. Since the electric field is constant for a given distance <em>r</em> from the axis of the cylinder we can write that:

\Phi = E \cdot 2\pi r \cdot L

Joining both our expressions we can get that:

E= \frac{\lambda}{2\pi \epsilon_0 \cdot r}

<h3 /><h3>Learn more</h3>
  • Description on Electric fields: brainly.com/question/8971780
  • Relation between electric fields and magnetism: brainly.com/question/2838625
  • How can we use electric charges: brainly.com/question/10427437
<h3>Keywords</h3>

Electrons, protons, electric field, cylinder, electric flux

5 0
2 years ago
Read 2 more answers
Other questions:
  • When compared to others, how is a greater velocity represented on a motion map?
    15·2 answers
  • F the radius of a sphere is increasing at the constant rate of 2 cm/min, find the rate of change of its surface area when the ra
    11·1 answer
  • Which transformation of energy occurs in a hydroelectric power plant? A. Potential to chemical energy B. Chemical to potential e
    10·2 answers
  • Assuming no air resistance, how far will a 0.0010 kg raindrop have fallen when it hits the ground 30.0 s later. Assume g = 9.8 m
    8·2 answers
  • A woman walks into a carpet store wearing high-heeled shoes with a circular heel of diameter 0.987 cm. To the dismay of the stor
    5·1 answer
  • A supersonic aircraft consumes 5320 imperial gallons of kerosene per hour of flight and flies an average of 14 hours per day. it
    13·1 answer
  • An airplane flies Minneapolis too Chicago in 74 minutes. If it is 572,000 meters from Minneapolis too Chicago what is the planes
    12·1 answer
  • The allowed energies of a quantum system are 0.0 eV, 5.0 eV , and 8.5 eV .
    7·1 answer
  • A fire woman dropped a person onto the safety net. Right
    9·1 answer
  • How do solar systems, galaxies, and the universe show different frames of reference about space?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!