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Levart [38]
3 years ago
6

An experimenter finds that no photoelectrons are emitted from a particular metal unless the wavelength of light is less than 295

nm. her experiment will require photoelectrons of maximum kinetic energy 2.4 ev. what frequency light should be used to illuminate the metal?
Physics
1 answer:
wariber [46]3 years ago
7 0
If the object, ends up with a positive charge, then it is missing electrons. if it is missing electrons, then it must have been removed form the object during the rubbing process.
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I dont know what pfp to put on today so I'm asking u guys....
Mandarinka [93]

Answer:

i think number 2 should be your pfp

5 0
2 years ago
A light wave passes through an aperture (that is, a narrow slit). When it does so, the degree to which the wave spreads out will
crimeas [40]

Explanation:

Single slit diffraction

Diffraction is the phenomenon of spreading out of waves as they pass through an aperture or around objects. Diffraction occurs when the size of the aperture or obstacle is of the same order of magnitude as the wavelength of the incident wave. For very small aperture sizes, the vast majority of the wave is blocked. in case of  large apertures the wave passes by or through the obstacle without any significant diffraction.

7 0
3 years ago
Find the speed of light in each of the following materials. (a) gallium phosphide m/s (b) carbon disulfide m/s (c) benzene
Oksanka [162]

Explanation:

We need to calculate the speed of light in each materials

(I). Gallium phosphide,

The index of refraction of Gallium phosphide is 3.50

Using formula of speed of light

v=\dfrac{c}{\mu}....(I)

Where, \mu = index of refraction

c = speed of light

Put the value into the formula

v=\dfrac{3\times10^{8}}{3.50}

v=8.6\times10^{7}\ m/s

(II) Carbon disulfide,

The index of refraction of Gallium phosphide is 1.63

Put the value in the equation (I)

v=\dfrac{3\times10^{8}}{1.63}

v=1.8\times10^{8}\ m/s

(III). Benzene,

The index of refraction of Gallium phosphide is 1.50

Put the value in the equation (I)

v=\dfrac{3\times10^{8}}{1.50}

v=2\times10^{8}\ m/s

Hence, This is the required solution.

7 0
3 years ago
In the 2016 Olympics in Rio, after the 50 mm freestyle competition, a problem with the pool was found. In lane 1 there was a gen
gogolik [260]

Answer:

Explanation:

still water speed is 50 m / 25.0 s = 2.00 m/s or 200 cm/s

In lane 1 the effective speed would be 201.2 cm/s

5000 cm / 201.2 cm/s = 24.85 s

The change is 25.00 - 24.85 = 0.15 s decrease in time

In lane 8, the effective speed would be 198.8 cm/s

5000 cm / 198.8 cm/s = 25.15 s

The change is 25.00 - 25.15 = 0.15 s increase in time

6 0
3 years ago
One property that makes electromagnetic waves differ from other types of waves is that they can
Phoenix [80]
That they travel in a vacuum.  All other waves require a medium in which they wave.
4 0
3 years ago
Read 2 more answers
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