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3 years ago

Describe the end behavior of a 14th degree polynomial with a positive leading coefficient.

1 answer:

4 0

The function will enter the graph graph in the upper left hand region and exit in the upper right hand region and overall the graph will be concave upwards.
For determining the end behavior of a polynomial, there is just 2 things to take notice of.
1. Is the leading coefficient positive or negative?
2. Is the degree of the polynomial odd or even?
For odd ordered polynomials, the curve starts in either quadrant II or III, and ends in quadrant IV, or I. Basically, if it's positive, the curve enters the graph somewhere in the lower left hand region, and exits the graph in the upper right hand region. If the coefficient is negative, it enters in the upper left hand region, and exits in the lower right hand region.
For even ordered polynomials, the graph is either concave upwards (positive leading coefficient) or concave downwards (negative leading coefficient).
In this problem, 14 is an even number and since the coefficient is positive, the function will enter the graph graph in the upper left hand region and exit in the upper right hand region and overall the graph will be concave upwards.

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Evaluate the expression -5|k+3| for k=-11

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So because I k+3 I will result always positive than

-5*I k+3 I for k= - 11 will be -5*I - 11 +3 I = - 5 *I -8 I = - 5*8 = -40

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3 years ago

A sample of 300 FM residents was taken and 135 said their favorite season was summer. Calculate a 99% confidence interval for th

erma4kov [3.2K]

Answer:

The 99% confidence interval for the proportion of FM residents whose favorite season is summer is between (0.376, 0.524).

The lower bound of this interval is 0.376.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 300, \pi = \frac{135}{300} = 0.45$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.45 - 2.575\sqrt{\frac{0.45*0.55}{300}} = 0.376$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.45 + 2.575\sqrt{\frac{0.45*0.55}{300}} = 0.524$

The 99% confidence interval for the proportion of FM residents whose favorite season is summer is between (0.376, 0.524).

The lower bound of this interval is 0.376.

3 0

3 years ago

Read 2 more answers

I give brainiest for right answers answer all

Step2247 [10]

$Hello$ $There!$

First 1: Store 3

Second 2: C.

Third: Marneisha

Four: 10

Five: Phone C.

Six: A.

Hopefully, this helps you!!

$AnimeVines$

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2 years ago

Read 2 more answers

If the number of employed persons equals 180 million, the number of unemployed persons equals 15 million, and the number of pers

beks73 [17]

Answer:

$\text{Unemployment rate}\approx 7.7\%$

$\text{Labor force participation rate}\approx 92.9\%$

Step-by-step explanation:

We have been given that the number of employed persons equals 180 million. The number of unemployed persons equals 15 million, and the number of persons over age 16 in the population equals 210 million. We are asked to find the unemployment rate and the labor force participation rate.

$\text{Unemployment rate}=\frac{\text{Number of unemployed person}}{\text{Labor force}}\times 100\%$