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skelet666 [1.2K]
3 years ago
12

Suppose triangle ABC has vertices at A(1, 0), B(10, 0), and C(2, 6). After a 60° counterclockwise rotation about the origin, ver

tex B' has coordinates (5, ?).

Mathematics
1 answer:
Artemon [7]3 years ago
3 0
Check the picture attached.

Let OB be the radius of circle with center O.

Let B' be the image of B after the described rotation

OB and OB' are sides of the equilateral triangle OBB'.

The x coordinate of B' is the midpoint of OB, that is 5.

In the right triangle B', point (5, 0) and B:

Distance point (5, 0) to B is 5
|B'B|=|OB|=10

so by the pythagorean theorem:

a= \sqrt{ 10^{2} - 5^{2} } = \sqrt{ 2^{2} *5^{2} - 5^{2} }= \sqrt{5^{2}(4-1)}=5 \sqrt{3} units



Answer: 5 \sqrt{3}

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Answer:

a)2 + 3 + 5 + 6 = 16

b)8a + b-9

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Step-by-step explanation:

We are given the following in the question:

1. Equivalent expression

2 + 3 + 5 + 6

Since all the terms are like terms, we can write,

2 + 3 + 5 + 6 = 16

2. Sum of given expression

(8a - 2b - 4) \text{ and } (3b - 5)\\ (8a - 2b - 4) + (3b -5)\\= 8a -2b -4 + 3b -5\\\text{Collecting the like terms}\\8a + (-2b+3b) + (-4-5)\\= 8a + b-9

3. Standard form of the expression

4(2a) + 7(-4b) + (3 \times c \times 5)\\=(8a) + (-28b) + (15c)\\=8a - 28b + 15c

which is the required standard form of the given expression.

8 0
3 years ago
What describes angle 5 and 6
astraxan [27]

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Your answer is B: Corresponding angles.

4 0
3 years ago
Read 2 more answers
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V125BC [204]

your answer would be 147°

solution:

since ∠x and ∠y are supplementary angles. they must add up to 180°

so ∠+∠y=180°

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=147

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