Answer:
I'm not really,
sure but I think non linear
Step-by-step explanation:
sorry if I'm wrong
I must assume that you meant the following:
10(Q-3R)
P = ----------------
R
Multiplying both sides by R, we get PR = 10R(Q-3R), or PR = 10RQ - 30R^2.
Rearranging these terms so that powers of R are in descending order:
30R^2 - 10RQ + PR = 0
Factoring out R, we get
R(30R - 10Q + P) = 0. This has two solutions:
R = 0, and 10Q - P
30R = 10Q - P, so that R = --------------
30
Answer:
(5,4)
Step-by-step explanation:
We have that the longer base of an isosceles trapezoid joins points (-3, -2) and (7, -2), and one endpoint of the shorter base is (-1, 4).
The best way to find the coordinates of the other endpoint is to draw or sketch the figure on a coordinate grid.
From the graph in the attachment the coordinates of the other endpoints is (5,4).