What are the prime factors of 63 in ascending order
2 answers:
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Answer:
8, 12, 16, 20, 24, 28, 32, 36
Step-by-step explanation:
the nth term of an arithmetic sequence is
= a₁ + (n - 1)d
a₁ is the first term and d the common difference
given a₁ = 4 and a₁₀= 40 , then
4 + 9d = 40 ( subtract 4 from both sides )
9d = 36 ( divide both sides by 9 )
d = 4
add d to each term to obtain the next term
4 + 4 = 8
8 + 4 = 12
12 + 4 = 16
16 + 4 = 20
20 + 4 = 24
24 + 4 = 28
28 + 4 = 32
32 + 4 = 36
the 8 terms between 4 and 40 are
8, 12, 16, 20, 24, 28, 32, 36
Final answer is *drumroll******
x=4
x=4