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omeli [17]
3 years ago
11

What is the distance between the points (-5, -9) and (-5,14 )?

Mathematics
1 answer:
netineya [11]3 years ago
4 0

Answer:

-4, 19

Step-by-step explanation:

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Can someone please answer. There is a picture. There is only one problem. Thank you so much!!!
Aleks [24]
Hello,

Answer C

center (0,0)
b=3
c=7==>a²=c²+b²=49+9=58

x²/58+y²/9=1

6 0
3 years ago
Question 6 Multiple Choice Worth 1 points)
Elza [17]

Answer:

Step-by-step explanation:

5 - (x + 5) > -2(x + 4)

5 - x - 5 > -2x - 8

-x > -2x - 8

-x + 2x > -8

x > -8

6 0
3 years ago
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Find CD, given that point G is the centroid of
andrey2020 [161]

let's recall that a Centroid in a triangle cuts the Medians into a 2:1 ratio, or namely CG : GD are in a 2: 1 ratio, we can also look at it that the side CD is 2/3 of CD whilst GD is 1/3 of CD, so

CG=\cfrac{2}{3}CD\implies 17.7=\cfrac{2CD}{3}\implies 3(17.7)=2CD \\\\\\ \cfrac{3(17.7)}{2}=CD\implies 26.55=CD

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2 years ago
Suppose that a researcher is designing a survey to estimate the proportion of adults in your state who oppose a proposed law tha
irinina [24]

Answer:

n=\frac{0.5 (1-0.5)}{(\frac{0.02}{1.96})^2}= 2401

So without prior estimation for the population proportion, using a confidence level of 95% if we want a margin of error about 2% we need al least a sample size of 2401.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

Solution to the problem

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

If solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)  

The margin of error desired for this case is ME= \pm 0.02 equivalent to 2% points

For this case we need to assume a confidence level, let's assume 95%. And since we don't have prior estimation for the population proportion of interest the best value to do an approximation is \hat p =0.5

In order to find the critical value we need to take in count that we are finding the margin of error for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:  

z_{\alpha/2}=\pm 1.96  

Now we have all the values needed and if we replace into equation (b) we got:

n=\frac{0.5 (1-0.5)}{(\frac{0.02}{1.96})^2}= 2401

So without prior estimation for the population proportion, using a confidence level of 95% if we want a margin of error about 2% we need al least a sample size of 2401.

5 0
3 years ago
Will mark brainliest!<br> (problem below)
Vlad [161]

Answer:

Joe

Hope this helps!

4 0
3 years ago
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