AC = 2 BD
Distance BD = √[(2.5+1)^2 +(3-3)^2]
Distance BD = √(3.5)^2
Distance BD = 3.5
AC = 2 * 3.5 = 7
Answer
d. 7
The value of distance between the station and the city in terms of miles which train and car travelled at interval of 2 hours is 129.6 miles.
<h3>What is the rate of speed?</h3>
The rate of speed is the rate at which the total distance is travelled in the time taken. Rate of speed can be given as,
r=d/t
Here, (d) is the distance travelled by the object and (t) is time taken but the object to cover that distance.
The train traveled 1/3 of the distance at 30 mph and the remaining distance at 40 mph. Let <em>t</em> is the time the train has taken to travel and x is the distance it travelled. Thus,

After two hour a car left the same station traveled the first 3 hours at 35 mph and the remaining distance at 51 mph. Let <em>t</em> is the time the car has taken to travel and x is the distance it travelled. Thus,

As t is same, thus put the value of t in this equation,

Thus, the value of distance between the station and the city in terms of miles which train and car travelled at interval of 2 hours is 129.6 miles.
Learn more about the rate of speed here:
brainly.com/question/359790
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Answer:
4.23
Step-by-step explanation:
3.68 + 0.21 + 0.25 + 0.01 + 0.08 = 4.23
You will first find the unit rate which is single in four hours so then multiply by triple which is 3 and then you get triple will be in 12 hours
95*18%
18%=0.18
95 x 0.18 =17.1
Now, multiply 17.1 by 5 = 85.5