Question

Point Q' is the image of Q(-7, -6) under the translation (x, y) + (x + 12, y + 8).

Answer 1

Answer:

The co-ordinates of Q' is (5,2).

Step-by-step explanation:

Given:

Pre-image point

Q(-7,-6)

To find Image point Q' after following translation.

$(x,y)\rightarrow (x+12,y+8)$

Solution:

Translation rules:

Horizontal shift:

$(x,y)\rightarrow (x+k,y)$

when $K>0$ the point is translated $k$ units to the right.

when $K$ the point is translated $k$ units to the left.

Vertical shift:

$(x,y)\rightarrow (x,y+k)$

when $K>0$ the point is translated $k$ units up.

when $K$ the point is translated $k$ units down.

Given translation $(x,y)\rightarrow (x+12,y+8)$ shows the point is shifted 12 units to the right and 8 units up.

The point Q' can be given as:

Q'=$(-7+12,-6+8)=(5,2)$

So, the co-ordinates of Q' is (5,2). (Answer)