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You are dealt two cards successively (without replacement) from a shuffled deck of 52 playing cards. Find the probability that t

icang [17]

Answer:

The probability that the first card is a Heart and the second card is a Spade is 0.064.

Step-by-step explanation:

A standard deck of 52 cards is shuffled and two cards are drawn without replacement.

The denominations of the cards are as follows:

Spades (S) = 13

Hearts (H) = 13

Diamonds (D) = 13

Clubs (C) = 13

Compute the probability of selecting a Heart first as follows:

$P(H)=\frac{13}{52}=0.25$

Compute the probability of selecting a Spade second as follows:

$P(S)=\frac{13}{51}=0.255$

Since the two cards are selected without replacement the second draw is independent of the other.

Then the probability that the first card is a Heart and the second card is a Spade is:

$P(1st\ H\cap 2nd\ S)=P(H)\times P(S)$

$=0.25\times 0.255\\=0.06375\\\approx 0.064$

Thus, the probability that the first card is a Heart and the second card is a Spade is 0.064.

4 0

3 years ago

Complementary Congruent Supplementary Similar

Lelu [443]

Answer:

complementary

Step-by-step explanation:

8 0

3 years ago

Solve the following question

White raven [17]

Answer:

g) $u^{4}\cdot v^{-1}\cdot z^{3}$ , h) $\frac{(x+4)\cdot (x+2)}{3\cdot (x-5)}$

Step-by-step explanation:

We proceed to solve each equation by algebraic means:

g) $\frac{u^{5}\cdot v}{z}\div \frac{u\cdot v^{2}}{z^{4}}$

1) $\frac{u^{5}\cdot v}{z}\div \frac{u\cdot v^{2}}{z^{4}}$ Given

2) $\frac{\frac{u^{5}\cdot v}{z} }{\frac{u\cdot v^{2}}{z^{4}} }$ Definition of division

3) $\frac{u^{5}\cdot v\cdot z^{4}}{u\cdot v^{2}\cdot z}$ $\frac{\frac{a}{b} }{\frac{c}{d} } = \frac{a\cdot d}{b\cdot c}$

4) $\left(\frac{u^{5}}{u} \right)\cdot \left(\frac{v}{v^{2}} \right)\cdot \left(\frac{z^{4}}{z} \right)$ Associative property

5) $u^{4}\cdot v^{-1}\cdot z^{3}$ $\frac{a^{m}}{a^{n}} = a^{m-n}$ /Result

h) $\frac{x^{2}-16}{x^{2}-10\cdot x + 25} \div \frac{3\cdot x - 12}{x^{2}-3\cdot x -10}$

1) $\frac{x^{2}-16}{x^{2}-10\cdot x + 25} \div \frac{3\cdot x - 12}{x^{2}-3\cdot x -10}$ Given

2) $\frac{\frac{x^{2}-16}{x^{2}-10\cdot x+25} }{\frac{3\cdot x - 12}{x^{2}-3\cdot x - 10} }$ Definition of division

3) $\frac{(x^{2}-16)\cdot (x^{2}-3\cdot x -10)}{(x^{2}-10\cdot x + 25)\cdot (3\cdot x - 12)}$ $\frac{\frac{a}{b} }{\frac{c}{d} } = \frac{a\cdot d}{b\cdot c}$

4) $\frac{(x+4)\cdot (x-4)\cdot (x-5)\cdot (x+2)}{3\cdot (x-5)^{2}\cdot (x-4) }$ Factorization/Distributive property

5) $\left(\frac{1}{3} \right)\cdot (x+4)\cdot (x+2)\cdot \left(\frac{x-4}{x-4} \right)\cdot \left[\frac{x-5}{(x-5)^{2}} \right]$ Modulative and commutative properties/Associative property

6) $\frac{(x+4)\cdot (x+2)}{3\cdot (x-5)}$ $\frac{a^{m}}{a^{n}} = a^{m-n}$ / $\frac{a}{b}\times \frac{c}{d} = \frac{a\cdot c}{b\cdot d}$ /Definition of division/Result