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madreJ [45]
3 years ago
12

Jonathan has a collection of 400 marbles. Blue marbles make up 17% percent of his collection.

Mathematics
1 answer:
raketka [301]3 years ago
5 0
So percent means parts out of 100 so 17%=17/100
400 marbles
17% of 400=blue
<span>'of' can be translated to multiply </span>
17%=17/100
17/100 ties 400=6800/100=68
<span>he has 68 blue marbles.</span>
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A sample of an unknown liquid has a volume of 24.0 mL and a mass of 6 g. What is its density?
Furkat [3]

Answer:

Hey there!

Density = Mass/Volume

Mass= 6g

Volume=24 mL, which is 24 cm^3

Density= 6g/24 cm^3

Density=0.25 g/cm^3

Let me know if this helps :)

5 0
3 years ago
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What is the surface area of the right cone below?<br>​
olga55 [171]

Answer:

54 is anwer.

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3 years ago
Find the components of the vertical force Bold Upper Fequalsleft angle 0 comma negative 8 right anglein the directions parallel
nydimaria [60]

Answer with Step-by-step explanation:

We are given that

F=<0,-8>=0i-8j=-8j

\theta=\frac{\pi}{3}

The component of force is divided into two direction

1.Along the plane

2.Perpendicular to the plane

1.The vector parallel to the plane will be=r=cos\frac{\pi}{3}i-sin\frac{\pi}{3}j=\frac{1}{2}i-\frac{\sqrt 3}{2}j

By using cos\frac{\pi}{3}=\frac{1}{2},sin\frac{\pi}{3}=\frac{\sqrt 3}{2}

Force along the plane will be=\mid F_x\mid=F\cdot r

Force along the plane will be =\mid F_x\mid=F\cdot (\frac{1}{2}i-\frac{\sqrt 3}{2}j)=-8j\cdot(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=8\times \frac{\sqrt 3}{2}=4\sqrt 3N

By using i\cdot i=j\cdoty j=k\cdot k=1,i\cdot j=j\cdot k=k\cdot i=j\cdot i=k\cdot j=i\cdot k=0

Therefore, force along the plane=\mid F_x\mid(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)

2.The vector perpendicular to the plane=r=-sin\frac{\pi}{3}-cos\frac{\pi}{3}=-\frac{\sqrt 3}{2}i-\frac{1}{2}j

The force perpendicular to the plane=\mid F_y\mid=F\cdot r=-8j(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

The force perpendicular to the plane=4N

Therefore, F_y=4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

Sum of two component of force=F_x+F_y=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)+4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

Sum of two component of force=2\sqrt 3i-6j-2\sqrt3 i-2j=-8j

Hence,sum of two component of forces=Total force.

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3 years ago
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ICE Princess25 [194]

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

x = w/3 - 2/3

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3 years ago
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devlian [24]
You have to isolate the (a) so you multiply the 2/3 by 3/2 and you have to do that to the right side. So -24 times 3/2 equals to -36. Therefore, a=-36. 
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3 years ago
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