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valentinak56 [21]
3 years ago
14

Formula semidesarrolada de 2, 3, 4 – Octa trieno

Chemistry
1 answer:
mixer [17]3 years ago
6 0

Answer:

octa

Explanation:

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Stella [2.4K]
Organic is the answer
5 0
3 years ago
Consider the following reaction: CO(g)+2H2(g) <--> CH3OH(g).
Andrew [12]

Answer:

123 is the equilibrium constant for the reaction.

Explanation:

CO(g)+2H_2(g)\rightleftharpoons CH_3OH(g)

Equilibrium concentration of reactants :

[CO]=0.115 M,[H_2]=0.116 M

Equilibrium concentration of products:

[CH_3OH]=0.190 M

The expression of an equilibrium constant is given by :

K_c=\frac{[CH_3OH]}{[CO][H_2]^2}

K_c=\frac{0.190 M}{0.115 M\times (0.116 M)^2}

K_c=122.78 \approx 123

123 is the equilibrium constant for the reaction.

4 0
3 years ago
Use the standard free energies of formation (ΔGf°) of each substance to determine the value of equilibrium constant K at 25 °C f
Greeley [361]

Answer:

k = 8,83x10³⁹

Explanation:

For the reaction:

CO₂(g) + 2H₂(g) ⇌ CH₃OH(l)

ΔG° = ΔGproducts - ΔGreactants

ΔG° = ΔGCH₃OH(l)  - (ΔGCO₂(g) + 2ΔGH₂(g)

As ΔGCH₃OH(l)  = -166,4 kJ/mol; ΔGCO₂(g) = -394,4 kJ/mol; ΔGH₂(g) = 0 kJ/mol

ΔG° = -166,4 kJ/mol - (-394,4 kJ/mol + 2×0 kJ/mol)

ΔG° = 228,0 kJ/mol

The ΔG could be defined as:

ΔG = -RT lnK

Where R is gas constant (8,314472x10⁻³ kJ/molK); Temperature is 25°C, 298,15K.

Replacing:

228,0 kJ/mol = 8,314472x10⁻³ kJ/molK×298,15K ln K

91,97 = ln k

K = 8,79x10³⁹ ≈ 8,83x10³⁹

I hope it helps!

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4 years ago
1.50μm2. Convert this to square meters.
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In scientific notation 1.5 square micrometers is 1.5e-12 square meters.
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What is the difference between melting and melting point
Yakvenalex [24]

Answer:

Melting Is when a substance is actually melting and melting point is a point at which a substance is able to melt.

4 0
4 years ago
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