Question

When a dilute solution of 20minutes of H2O2 solution total volume of oxygen was collected was 120cm³ in just 15minutes. Calculate the rate of formation of oxygen.

Answer 1

Answer:

$\large \boxed{\text{8.0 cm}^{3}\cdot \text{min}^{-1}}$

Explanation:

The rate of formation of O₂ is the change in volume divided by the change in time.

For the reaction  

$\rm 2H_{2}O_{2}\longrightarrow \, 2H_{2}O+ O_{2} \\\text{rate} = \dfrac{\Delta V}{\Delta t } = \dfrac{\text{120 cm}^{3}}{\text{ 15 min}} = \textbf{8.0 cm}^{\mathbf{3}}\cdot \textbf{min}^{\mathbf{-1}}\\\\\text{The rate of formation of oxygen is \large \boxed{\textbf{8.0 cm}^{\mathbf{3}}\cdot \textbf{min}^{\mathbf{-1}}} }$