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3 years ago

How many moles are in 105.7 grams of aluminum

Chemistry

1 answer:

Inessa [10]3 years ago

3 0

Answer:

3.918 mol Al

Explanation:

To convert between moles and grams, you have to use the molar mass of the substance. The molar mass of aluminum is 26.98 g/mol. You use this as the unit converter.

$105.7gAl *\frac{1molAl}{26.98gAl} =3.91771683molAl$

Round the number to the lowest number of significant figures; 3.918 mol Al

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Leni [432]

Answer: 457.8

Explanation:

345.8*225/703.55

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3 years ago

The density of liquid oxygen at its boiling point is 1.14 kg/L , and its heat of vaporization is 213 kJ/kg . How much energy in

-Dominant- [34]

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3 years ago

flammable liquid is being pumped out of a drum into a bucket using a hand pump. describe an appropriate grounding and bonding pr

lutik1710 [3]

When transferring flammable liquids from storage drums to smaller electrically conductive containers, bonding and grounding are required. In any workplace, you should do the same whenever you move these liquids between conductive containers.

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3 0

1 year ago

In a reaction, 24.9 L of N2 reacts with excess Hy to produce NH3. How many liters of NH3

Amiraneli [1.4K]

Answer:

A. 49.8L of NH3.

B. 33.83g.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is shown below:

N2 + 3H2 —> 2NH3

A. From the balanced equation above,

1L of N2 produced 2L of NH3.

Therefore, 24.9L of N2 will produce = 24.9 x 2 = 49.8L of NH3.

Therefore, 49.8L of NH3 is produced from the reaction.

B. Determination of the mass NH3 produced.

First, we shall determine the number of mole of NH3 produced. This can be obtained as follow:

Volume (V) = 49.8L

Pressure (P) = 97.8 kPa = 97.8/101.325 = 0.97atm

Temperature (T) = 23.7°C = 23.7°C + 273 = 296.7K

Gas constant (R) = 0.082atm.L/Kmol

Number of mole (n) =...?

PV = nRT

n = PV /RT

n = (0.97 x 49.8) / (0.082 x 296.3)

n = 1.99 mole

Next, we shall convert 1.99 mole to NH3 to grams. This is illustrated below:

Number of mole NH3 = 1.99 mole

Molar mass of NH3 = 14 + (3x1) = 17g/mol

Mass of NH3 =..?

Mass = mole x molar Mass

Mass of NH3 = 1.99 x 17

Mass of NH3 = 33.83g

Therefore, 33.83g of NH3 is produced.

6 0

4 years ago

7. An 8.92 kilogram bar of steel at 25°C is heated in order to shape it into a beam. The amount of heat energy

kobusy [5.1K]

Answer:

1279 °C

Explanation:

Data Given:

Amount of Heat absorb = 5.82 x 10³ KJ

Convert KJ to J

1 KJ = 1000 J

5.82 x 10³ KJ = 5.82 x 10³ x 1000 = 5.82 x10⁶ J

mass of sample = 8.92 Kg

Convert Kg to g

1 kg = 1000 g

8.92 Kg = 8.92 x 1000 = 8920 g

Cs of steel = 0.51 J/g °C

change in temperature = ?

Solution:

Formula used

Q = Cs.m.ΔT

rearrange the above equation to calculate the mass of steel sample

ΔT = Q / Cs.m .... . . . . . (1)

Where:

Q = amount of heat

Cs = specific heat of steel = 0.51 J/g °C

m = mass

ΔT = Change in temperature

Put values in above equation 1

ΔT = 5.82 x10⁶ J / 0.51 (J/g °C) x 8920 g

ΔT = 5.82 x10⁶ J /4549.2 (J/°C)

ΔT = 1279 °C

So,

change in temperature = 1279 °C

4 0

3 years ago