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Fantom [35]
3 years ago
11

There were 6 purple socks and 4 orange socks in a drawer. Zucky picked one sock without looking and then another without looking

(or replacing the first). What is the probability that he picked 2 purple socks?
Mathematics
1 answer:
postnew [5]3 years ago
8 0

Answer: 1/3

Step-by-step explanation:

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How much sales tax would you pay on a bike that costs $225 and sales tax is 5.3%?​
mina [271]
The tax would be $11.93

Hope this helps
8 0
2 years ago
Please help me with this question, thanks.
arlik [135]

Answer:

  2.48×10^13 miles

Step-by-step explanation:

There are about (365.25 days)(86400 seconds/day) = 31,557,600 seconds in one year. There are 1609.344 meters in one mile. So, the conversion can be written as ...

  (4.22 ly) (3×10^8 m/s) (3.15576×10^7 s/yr) / (1.609344×10^3 m/mi)

  = 4.22×3×3.15576/1.609344×10^(8+7-3) mi

  ≈ 24.8×10^12 mi

4.22 light years is about 2.48×10^13 miles

8 0
3 years ago
The perimeter of a square is 44. Find the length of a diagonal.
julsineya [31]
If the perimeter is 44 the the diagonal is 22
7 0
3 years ago
Read 2 more answers
for any positive integer n, the sum of the first n positive integers equals n(n 1)/2. what is the sum of all the even integers b
marusya05 [52]

The sum of all the even integers between 99 and 301 is 20200

To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.

In this case, the first even integer will be 100 and the last even integer will be 300.

nth term of the AP = first term + (n-1) x common difference

               ⇒    300 = 100 + (n-1) x 2

Therefore, n = (200 + 2 )/2 = 101

That is, there are 101 even integers between 99 and 301.

Sum of the 'n' terms in an AP = n/2 ( first term + last term)

                                                = 101/2 (300+100)

                                                = 20200

Thus sum of all the even integers between 99 and 301 = 20200

Learn more about arithmetic progressions at brainly.com/question/24592110

#SPJ4        

7 0
1 year ago
There are 7 males and 5 females and we need to select 4 different people. how many ways can we select 4 people?
saul85 [17]

\displaystyle \binom{12}{4}=\dfrac{12!}{4!8!}=\dfrac{9\cdot10\cdot11\cdot12}{2\cdot3\cdot4}=495

5 0
3 years ago
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