The test statistic for the hypothesis would be 1.413.
Given that the participants in its new diet program lose, on average, more than 13 pounds and the mean weight loss of these participants as 13.8 pounds with a standard deviation of 3.1 pounds.
The objective is to text the advertisement's claim that participants in new diet program lose weight, on average, more than 13 pounds.
Hypothesis:
Null hypothesis:H₀:μ=13
Alternative hypothesis:Hₐ:μ>13
Here, μ be the mean weight loss of all participants.
n=30,
Degree of freedom n-1=30-1=29
=13.8 and s=3.1
To test the null hypothesis H₀, the value of test static would be calculated as follows:
Hence, the value of the test static for the hypothesis with the mean weight loss of these participants as 13.8 pounds with a standard deviation of 3.1 pounds is 1.413.
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3x-4=-31
+4 +4
3x=27
X=9
Hope this helps
Answer:
Step-by-step explanation:
Eight
590 = 1800 e^(-0.4t) Divide by 1800
0.32778 = e^(-0.4t) Put the value for e in the denominator.
0.32778 = 1 / e^(0.4t) Notice the sign's gone. Multiply both sides by e^(0.4t)
0.32778 *e^(0.4t) = 1 Divide by 0.32778
e^(0.4t) = 3.0508 Take the natural log of both sides.
0.4t = 1.11542 Divide both sides by 0.4
t = 2.78855
You should put this in the original equation to see if it checks. It does.
=============================
Nine
3^(3 - 3x) + 6 = 42 Subtract 6 from both sides
3^(3 - 3x) = 36 Take the log of both sides.
(3 - 3x) ln(3) = ln 36
(3 - 3x) *1.098612 = 3.58352 Divide by 1.098612
3 - 3x = 3.26186 Subtract 3 from both sides
- 3x = 0.26186 Divide by - 3
x = - 0.087287
Answer:
1. 9/16 * 12/13 = 27/52
2. 7/10 * 5/28 = 1/8
Step-by-step explanation:
1.
9 / 16 * 12/13
9 * 12 = 108
16 * 13 = 208
108 / 208
Simplify:
27/52
2.
7 / 10 * 5 / 28
7 * 5 = 35
10 * 28 = 280
Simplify:
1/8
500/4= 125
she has written 125 words and needs to write 375 more
