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2 years ago

What is the product (4x)( -3x^6)(-7x^3)

Mathematics

1 answer:

11111nata11111 [884]2 years ago

7 0

Answer:

84x^10

Step-by-step explanation:

The coefficients multiply, and the exponents add.

(4x)( -3x^6)(-7x^3) = (4)(-3)(-7)x^(1+6+3) = 84x^10

The rule for exponents is ...

(x^a)(x^b) = x^(a+b)

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If 27^x=9/3^x ,then the value of x is

Korolek [52]

Answer:

x = 0.5

Step-by-step explanation:

Well, we have in this case a exponent equation

$27^{x} = \frac{9}{3^{x}}$

Factoring 27 = $3^{3}$

Our new equation is:

$3^{3x}=\frac{3^{2}}{3^{x}}$

Applying the property of exponents, on the right we'll have just like that:

$3^{3x} = 3^{2-x}$

now, it's easy to solve this equation. You must solve 3x = 2 - x because the basis of these exponents are equal.

3x = 2 - x

3x + x = 2

4x = 2

x = 1/2 or 0.5

5 0

2 years ago

What is the volume of the cone to the nearest cubic meter? (Use π = 3.14.) Refer to your STAAR 8th Grade Math Reference Sheet f

prisoha [69]

Answer:

V≈83.78

Step-by-step explanation:

The formula to find the volume of a cone is V=πr(squared) h/3

Steps

V= π (4)^2 5/3

V= π (16) 1.66666666667

V = 50.2654824574 * 1.66666666667

v= 83.7758040958

Round

V = 83.78

7 0

1 year ago

Read 2 more answers

X²y-2xy+y=?????????<br><br><br><br>

dexar [7]

Answer:

$y(x - 1)^{2}$

Step-by-step explanation:

$x²y-2xy+y$

$y {x}^{2} −2xy+y$

$y( {x}^{2} −2x)+y \times 1$

$y ( {x}^{2} - 2x + 1)$

$y(x - 1)^{2}$

<h3>Hope it is helpful....</h3>

4 0

2 years ago

What is the simple interest on a loan of $310 for 4 months at 12% per year ?

denpristay [2]

Answer:

$ 12.4

Step-by-step explanation:

i have got $ 12.4

5 0

3 years ago

Read 2 more answers

Find the values of m and b that make the following function differentiable.

KengaRu [80]

$f(x)=\begin{cases}x^2&\text{for }x\le2\\mx+b&\text{for }x>2\end{cases}$

In order to be differentiable everywhere, $f$ must first be continuous everywhere, which means the limits from either side as $x\to2$ must be the same and equal to $f(2)$ . By definition, $f(2)=2^2=4$ , and

$\displaystyle\lim_{x\to2^-}f(x)=\lim_{x\to2}x^2=4$

$\displaystyle\lim_{x\to2^+}f(x)=\lim_{x\to2}(mx+b)=2m+b$

so we need to have $4m+b=4$ .

For $f$ to be differentiable at $x=2$ , the derivative needs to be continuous at $x=2$ , i.e.

$\displaystyle\lim_{x\to2^-}f'(x)=\lim_{x\to2^+}f'(x)$

We then need to have

$\displaystyle\lim_{x\to2}2x=\lim_{x\to2}m\implies\boxed{m=4}$

Then

$2m+b=4\implies\boxed{b=-4}$

7 0

2 years ago