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3 years ago

A good way to de-magnetize something is to

Physics

2 answers:

FromTheMoon [43]3 years ago

8 0

Answer:

B. place it in a magnetic field

Ipatiy [6.2K]3 years ago

5 0

Answer:heat it

Explanation:

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During an observation, it was noticed that light travels as bundles containing certain amounts of energy. What does this evidenc

blsea [12.9K]

Answer: B. It demonstrates a behavior or particles.

Explanation: I took the test and got it right

6 0

4 years ago

What are the chemical properties of elements related to?

MAVERICK [17]

<span>The chemical properties of ANY atom are found in how they react with other elements.

A. An element's symbol - Nothing to do with reactions

B. The average atomic mass -The mass doesn't react

C. The number of electrons that occupy the outer shell - the only part of the electrons that move, SO they are involved in the reactions (answer)

D. The total number of electrons - The inner electrons cannot move from the atom unless there is ALOT of energy given to them, so these cannot react and would not contribute to the chemical properties.</span>

3 0

3 years ago

A string of length L, mass per unit length \mu, and tension T is vibrating at its fundamental frequency. What effect will the fo

viva [34]

The fundamental frequency on a vibrating string is given by:

$f=\frac{1}{2L}\sqrt{\frac{T}{\mu}}$

where

L is the length of the string

T is the tension

$\mu$ is the mass per unit length of the string

Keeping this equation in mind, we can now answer the various parts of the question:

(a) The fundamental frequency will halve

In this case, the length of the string is doubled:

L' = 2L

Substituting into the expression of the fundamental frequency, we find the new frequency:

$f'=\frac{1}{2(2L)}\sqrt{\frac{T}{\mu}}=\frac{1}{2}(\frac{1}{2L}\sqrt{\frac{T}{\mu}})=\frac{f}{2}$

So, the fundamental frequency will halve.

(b) the fundamental frequency will decrease by a factor $\sqrt{2}$

In this case, the mass per unit length is doubled:

$\mu'=2\mu$

Substituting into the expression of the fundamental frequency, we find the new frequency:

$f'=\frac{1}{2L}\sqrt{\frac{T}{2 \mu}}=\frac{1}{\sqrt{2}}(\frac{1}{2L}\sqrt{\frac{T}{\mu}})=\frac{f}{\sqrt{2}}$

So, the fundamental frequency will decrease by a factor $\sqrt{2}$ .

(c) the fundamental frequency will increase by a factor $\sqrt{2}$

In this case, the tension is doubled:

$T'=2T$

Substituting into the expression of the fundamental frequency, we find the new frequency:

$f'=\frac{1}{2L}\sqrt{\frac{2T}{\mu}}=\sqrt{2}(\frac{1}{2L}\sqrt{\frac{T}{\mu}})=\sqrt{2}f$

So, the fundamental frequency will increase by a factor $\sqrt{2}$ .

8 0

3 years ago

A clothes dryer uses about 30 amps of current from a 240 volt line. How much power does it use?

Aneli [31]

Not sure if this answer is write or wrong but i think its <span>4500 watts

</span>

8 0

3 years ago

Read 2 more answers

A block of wood 3.0 cm on each side has a mass of 27g. what is the density of this block?

schepotkina [342]

The block of wood is 3cm on each side so it is a cube. The volume of a cube is given by s^3. So the volume of this block is 3cm x 3cm x3 cm = 27 cm^3. density = mass/volume =27 g / 27 cm^3 = 1 g/cm^3

8 0

3 years ago