True
Explanation:
Average speed is a scalar magnitude as opposed to average velocity which is a vector. The unit of measurement in the International System (S.I.) of the average speed is the meter per second (m/s).
The distance traveled by the sprinter in meters is determined as 1.88 m.
<h3>Acceleration of the sprinter</h3>
The acceleration of the sprinter is the rate of change of velocity of the sprinter with time.
The acceleration of the sprinter is calculated as follows;
Apply Newton's second law of motion as follows;
F = ma
a = F/m
where;
- F is the applied force by the sprinter
- m is mass of the sprinter
- a is acceleration of the sprinter
a = 693 N / 64 kg
a = 10.83 m/s²
<h3>Distance traveled by the sprinter</h3>
The distance traveled by the sprinter is calculated as follows;
s = ut + ¹/₂at²
where;
- u is initial velocity = 0
s = ¹/₂at²
where;
- t is time of motion
- a is acceleration
s = (0.5)(10.83)(0.59²)
s = 1.88 m
Thus, the distance traveled by the sprinter in meters is determined as 1.88 m.
Learn more about distance here: brainly.com/question/2854969
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Answer:
0.89 g/cm^3 = 890 kg/m^3
Explanation:
Cross sectional area of U-tube ( A ) = 1.00 cm^2
volume of oil ( V ) = 5.00 cm^3
change between top surface = 0.550 cm
height of oil = 5 cm ( volume / area )
height of water = 5 - 0.550 = 4.45 cm
pressure at the oil-water junction = Pressure on the second side of the U-tube at same level
Po * g * Hoil = Pw * g * Hwater
Po * 5 = 1 * 4.45
∴ Density of oil ( Po ) = 4.45 / 5 g/cm^3 = 0.89 g/cm^3
Yes. It's (speed squared)/(radius of the circle).
Answer:
The magnitude of the induced voltage in the loop is 20 mV.
Explanation:
given;
length of loop, L = 0.43 m
width of loop,w = 0.43 m
velocity of moved loop, v = 0.15m/s
magnetic field strength,B = 0.31 T
To determine the magnitude of the induced voltage in the loop, we apply Faraday's law;
magnitude induced E.M.F = BLv
magnitude induced E.M.F = 0.31 x 0.43 x 0.15 = 0.02 V = 20 mV
Therefore, the magnitude of the induced voltage in the loop is 20 mV.
