Protein channels in the cell membrane
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The system of springs and shock absorbers by which a vehicle is cushioned from road conditions.</span>
Answer:
a. 0.27 = Kc
b. 8.19×10⁻⁵ = Kp
Explanation:
The reaction is this: 3H₂(g) + N₂ (g) ⇄ 2NH₃ (g)
As we have the moles of each in the equilibrium and the volume is 1L, we assume the concentrations as molarity.
1.6981 mol/L → H₂
0.5660 mol/L → N₂
0.8679 mol/L → NH₃
Let's make the expression for Kc
Kc = [NH₃]² / [N₂] . [H₂]³
Kc = 0.8679² / 0.5660 . 1.6981³
Kc = 0.27
Let's calculate Kp, derivated from Kc
Kp = Kc . (RT)^Δn where:
Δn is the difference between final moles - initial moles. It is governed by stoichiometry. For this case 2 - (1+3) = -2
Δn it is always for gases
R is the Ideal gases constant
T is Absolute T°
Let's replace data → 0.27 . (0.082 . 700K)⁻² = Kp
8.19×10⁻⁵ = Kp
Answer:
a) 5.4 * 10^-4 moles
b) 8.2 moles
c) 0.26 moles
d) 20.76 moles
Explanation:
a)Since 1 mole of a substance has 6.02 * 10^23 atoms
x moles is present in 3.25 x 1020 atoms of lead
3.25 x 1020 atoms of lead/6.02 * 10^23 atoms = 5.4 * 10^-4 moles
b) Since 1 mole of a substance has 6.02 * 10^23 molecules
x moles is present in 4.96 x 1024 molecules of glucose
x = 4.96 x 1024 molecules of glucose/6.02 * 10^23 molecules = 8.2 moles
c) Since 1 mole of a substance has 6.02 * 10^23 formula units
x moles is present in 1.56 x 1023 formula units of sodium hydroxide
x = 1.56 x 1023 formula units /6.02 * 10^23 = 0.26 moles
d) Since 1 mole of a substance has 6.02 * 10^23 ions
x moles is present in 1.25 x 1025 copper(ll) ions
x = 1.25 x 1025 copper(ll) ions/6.02 * 10^23 ions = 20.76 moles