Covalent bonds or interactions are overcome when a nonmetal extended network melts.
Typically, nonmetals form covalent bonds with one another. A polyatomic ion's atoms are joined by a form of link called covalent bonding. A covalent bond requires two electrons, one from each of the two atoms that are connecting.
One technique to depict the formation of covalent connections between atoms is with Lewis dot formations. The number of unpaired electrons and the number of bonds that can be formed by each element are typically identical. Each element needs to share an unpaired electron in order to establish a covalent bond.
Therefore, covalent bonds or interactions are overcome when a nonmetal extended network melts.
Learn more about covalent bonds here;
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The mass of CO₂ gas = 4.312 g
<h3>Further explanation</h3>
Reaction
NaHCO₃ (s) + HCl (aq) → NaCl (aq) + H₂O (aq) + CO₂ (g)
Find limiting reactant
mol NaHCO₃
![\tt \dfrac{8.24}{84,007 }=0.098](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B8.24%7D%7B84%2C007%20%7D%3D0.098)
mol HCl
![\tt \dfrac{4.41}{36.5}=0.121](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B4.41%7D%7B36.5%7D%3D0.121)
Limiting reactant : NaHCO₃ (smaller)
mol CO₂ = mol NaHCO₃ = 0.098
mass CO₂ :
![\tt 0.098\times 44=4.312~g](https://tex.z-dn.net/?f=%5Ctt%200.098%5Ctimes%2044%3D4.312~g)
The mass percentage is 15.1465%.
Answer:
V ∝ abc
Explanation:
This task is a joint variation task involving only direct proportionality:
Direct variation is one in which two variables are in direct proportionality to each other. This means that as one increases, the other variable also increases and vice - versa.
Joint variation is one in which one variable is dependent on two or more variables and varies directly as each of them.
In this exercise:
If a ∝ b and a ∝ c, then a ∝ bc
Taking the above three proportionalities,
V ∝ a ∝ b ∝ c
V ∝ a ∝ bc
V ∝ abc
Answer:
For H3O concentration you do 10^-pH so if pH is 5 then H3O+ is 10^-5= 1*10^-5 H3O+ ions
For OH is one extra step. First find H3o+ ions using equation above then you have to use that to divide 1*10^-14
So if pH is 5....the H3O+ is 1*10^-5 then OH- = (1*10^-14)/(1*10^-5) = 1*10^-9 OH ions
as far as acid/base pH 0-6 is Acid 8-14 is Base. pH of 7 is neutral. Recheck your work *hint* *hint* water is neutral. Spit is above 7 so is base.