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3 years ago

5.50 L of a 0.190 M CaCl2M CaCl2 solution How do you find Grams?

Chemistry

1 answer:

Firdavs [7]3 years ago

6 0

Answer:

115.891

Explanation:

Molarity is equal to moles/liters so to get moles we multiply molarity by liters, after this we multiply the moles by the total atomic weight of the compound to get grams

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Calculate the mass in grams of carbon dioxide produced from 11.2 g of octane (C8H18) in the reaction above.

Ray Of Light [21]

Answer:

34.6g

Explanation:

Given parameters:

Mass of Octane = 11.2g

Reaction expression;

2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O

Mass of octane = 11.2g

Unknown:

Mass of carbon dioxide produced = ?

Solution:

From the balanced reaction equation;

2 mole of octane produced 16 moles of carbon dioxide

From the given specie, let us find the number of moles;

Number of moles = $\frac{mass}{molar mass}$

Molar mass of C₈H₁₈ = 8(12) + 18(1) = 114g/mole

Number of moles of octane = $\frac{11.2}{114}$ = 0.098mole

2 mole of octane produced 16 moles of carbon dioxide

0.098 mole of octane will produce $\frac{0.098 x 16}{2}$ = 0.79mole of CO₂

Mass of CO₂ = number of moles x molar mass

Molar mass of CO₂ = 12 + 2(16) = 44g/mol

Mass of CO₂ = 0.79 x 44 = 34.6g

8 0

3 years ago

Violet light has a wavelength of 422 nm, how much energy is found in this photon of violet light?

pashok25 [27]

Answer:

3.025eV

Explanation:

Energy of a photon is given by

E=hν

Where h is the Planck's constant

And ν represents the frequency of the photon .

Now for violet light wavelength λ=410nm= 410x10^-9m

By using the formula ν=c/λ

where c represents speed of light I.e 3 x 10^8 m/s

Calculating energy of violet photon we have

E=hc/λ

h=6.626 x 10^-34 J.s

On inserting the value in the formula , we get

E= 4.848 x 10^-19 Joules

To convert it into electron volts we need to divide it by 1.602 x10^-19.

The final result what we have is E=3.026eV.

Note: the result calculated is according to the above value . result may vary according to the values taken .

3 0

3 years ago

A frictionless piston cylinder device is subjected to 1.013 bar external pressure. The piston mass is 200 kg, it has an area of

Bad White [126]

Answer:

a) $T_{2} = 360.955\,K$ , $P_{2} = 138569.171\,Pa\,(1.386\,bar)$ , b) $T_{2} = 347.348\,K$ , $V_{2} = 0.14\,m^{3}$

Explanation:

a) The ideal gas is experimenting an isocoric process and the following relationship is used:

$\frac{T_{1}}{P_{1}} = \frac{T_{2}}{P_{2}}$

Final temperature is cleared from this expression:

$Q = n\cdot \bar c_{v}\cdot (T_{2}-T_{1})$

$T_{2} = T_{1} + \frac{Q}{n\cdot \bar c_{v}}$

The number of moles of the ideal gas is:

$n = \frac{P_{1}\cdot V_{1}}{R_{u}\cdot T_{1}}$

$n = \frac{\left(101,325\,Pa + \frac{(200\,kg)\cdot (9.807\,\frac{m}{s^{2}} )}{0.15\,m^{2}} \right)\cdot (0.12\,m^{3})}{(8.314\,\frac{Pa\cdot m^{3}}{mol\cdot K} )\cdot (298\,K)}$

$n = 5.541\,mol$

The final temperature is:

$T_{2} = 298\,K +\frac{10,500\,J}{(5.541\,mol)\cdot (30.1\,\frac{J}{mol\cdot K} )}$

$T_{2} = 360.955\,K$

The final pressure is:

$P_{2} = \frac{T_{2}}{T_{1}}\cdot P_{1}$

$P_{2} = \frac{360.955\,K}{298\,K}\cdot \left(101,325\,Pa + \frac{(200\,kg)\cdot (9.807\,\frac{m}{s^{2}} )}{0.15\,m^{2}}\right)$

$P_{2} = 138569.171\,Pa\,(1.386\,bar)$

b) The ideal gas is experimenting an isobaric process and the following relationship is used:

$\frac{T_{1}}{V_{1}} = \frac{T_{2}}{V_{2}}$

Final temperature is cleared from this expression:

$Q = n\cdot \bar c_{p}\cdot (T_{2}-T_{1})$

$T_{2} = T_{1} + \frac{Q}{n\cdot \bar c_{p}}$

$T_{2} = 298\,K +\frac{10,500\,J}{(5.541\,mol)\cdot (38.4\,\frac{J}{mol\cdot K} )}$

$T_{2} = 347.348\,K$

The final volume is:

$V_{2} = \frac{T_{2}}{T_{1}}\cdot V_{1}$

$V_{2} = \frac{347.348\,K}{298\,K}\cdot (0.12\,m^{3})$

$V_{2} = 0.14\,m^{3}$

4 0

4 years ago

Salt is often added to water to raise the boiling point to heat food more quickly. if you add 30.0g of salt to 3.75kg of water,

sammy [17]

Assuming an ebullioscopic constant of 0.512 °C/m for the water, If you add 30.0g of salt to 3.75kg of water, the boiling-point elevation will be 0.140 °C and the boiling-point of the solution will be 100.14 °C.

<h3>What is the boiling-point elevation?</h3>

Boiling-point elevation describes the phenomenon that the boiling point of a liquid will be higher when another compound is added, meaning that a solution has a higher boiling point than a pure solvent.

Step 1: Calculate the molality of the solution.

We will use the definition of molality.

b = mass solute / molar mass solute × kg solvent

b = 30.0 g / (58.44 g/mol) × 3.75 kg = 0.137 m

Step 2: Calculate the boiling-point elevation.

We will use the following expression.

ΔT = Kb × m × i

ΔT = 0.512 °C/m × 0.137 m × 2 = 0.140 °C

where

ΔT is the boiling-point elevation
Kb is the ebullioscopic constant.
b is the molality.
i is the Van't Hoff factor (i = 2 for NaCl).

The normal boiling-point for water is 100 °C. The boiling-point of the solution will be:

100 °C + 0.140 °C = 100.14 °C

Learn more about boiling-point elevation here: brainly.com/question/4206205

7 0

2 years ago

An overseas flight leaves New York in the late afternoon and arrives in London 8.50 hours later. The airline distance from New Y

Evgesh-ka [11]

Answer:

v = 658.82 km/h

Explanation:

The distance between New York and London is $5.6\times 10^3\ km$

Time taken from New York to London is 8.5 hours

We need to find the average speed of the plane.

Total distance covered divided by the total time taken is equal to the average speed of an object. So,

$v=\dfrac{d}{t}\\\\v=\dfrac{5.6\times 10^3\ km}{8.5\ h}\\\\v=658.82\ km/h$

So, the average speed of the plane is 658.82 km/h.

4 0

3 years ago