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Pavlova-9 [17]
3 years ago
5

Which of these electromagnetic waves has the shortest wavelength? radio waves infrared waves x-rays ultraviolet waves light wave

s?
Physics
2 answers:
padilas [110]3 years ago
6 0
X-rays have the shortest wavelength.

Hope this helped,, have a great day! :D
IRINA_888 [86]3 years ago
6 0
Radio waves is the answer
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What evidence do we have that the planets travel around the sun?
Softa [21]

Answer : The four seasons

Explanation:

5 0
3 years ago
Four model rockets are launched in a field. The mass of each rocket and the
TiliK225 [7]

Answer: it is rocket 2

Explanation: I just took the test

Hope it's the right answer for you

4 0
4 years ago
An undersea research chamber is spherical with an external diameter of 5.50 m . The mass of the chamber, when occupied, is 87600
dmitriy555 [2]

Answer:

the buoyant force on the chamber is F = 7000460 N

Explanation:

the buoyant force on the chamber is equal to the weight of the displaced volume of sea water due to the presence of the chamber.

Since the chamber is completely covered by water, it displaces a volume equal to its spherical volume

mass of water displaced = density of seawater * volume displaced

m= d * V , V = 4/3π* Rext³

the buoyant force is the weight of this volume of seawater

F = m * g = d * 4/3π* Rext³ * g

replacing values

F = 1025 kg/m³ * 4/3π * (5.5m)³ * 9.8m/s² = 7000460 N

Note:

when occupied the tension force on the cable is

T = F buoyant - F weight of chamber  = 7000460 N - 87600 kg*9.8 m/s² = 6141980 N

4 0
4 years ago
The bus, at location A, is traveling at 30 m/s when it is shifted to neutral and allowed to
sertanlavr [38]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The velocity of the bus at B is v_B= 31.6\  m/s

Explanation:

Let's take  position B as base point .

From the diagram  height between point B and A ia mathematically evaluated as

        h_A  = 60 -55

      h_A  = 5 \ m

From the question we are told that

   The velocity at location A is  v_A = 30 m/s

       

     According the law of conservation of energy

          PE_A + KE_A = KE_B

Where PE_A is the potential energy at A which is mathematically represented as

          PE_A = mgh_A

KE_A is the kinetic energy energy at A which is mathematically represented as

            KE_A = \frac{1}{2} mv^2_A

KE_B is the  kinetic energy at A which is mathematically represented as

          KE_B = \frac{1}{2} mv_B^2

Where v_B is the velocity at location B

So

      mgh_A + \frac{1}{2} mv_A^2 = \frac{1}{2} mv_B^2

Making v_B the subject of the formula

       v_B=  \sqrt{\frac{gh_A + \frac{1}{2} v_A^2 }{0.5} }

Substituting values

       v_B=  \sqrt{\frac{(9.8 * 5) + \frac{1}{2} 30^2 }{0.5} }

        v_B= 31.6\  m/s

7 0
3 years ago
A 22-g bullet traveling 240 m/s penetrates a 2.0-kg block of wood and emerges going 150 m/s. If the block is stationary on a fri
sveta [45]

Answer:

After the bullet emerges the block moves at 0.99 m/s

Explanation:

Given;

mass of bullet, m₁ = 22 g = 0.022 kg

initial speed of the bullet, u₁ = 240 m/s

final speed of the bullet, v₁ = 150 m/s

mass of block, m₂ = 2.0 kg

initial speed of the block, u₂ = 0

Let the final speed of the block = v₂

Apply principles of conservation of linear momentum;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

0.022 x 240 + 2 x 0 = 0.022 x 150 + 2v₂

5.28 = 3.3 + 2v₂

5.28 - 3.3 = 2v₂

1.98 = 2v₂

v₂ = 1.98 / 2

v₂ = 0.99 m/s

Therefore, after the bullet emerges the block moves at 0.99 m/s

3 0
4 years ago
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