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Minchanka [31]
3 years ago
9

You are explaining why astronauts feel weightless while orbiting in the space shuttle. Your friends respond that they thought gr

avity was just a lot weaker up there. Convince them and yourself that it isn't so by calculating the acceleration of gravity 608 km above the Earth's surface in units of g. (The mass of the Earth is 5.97 x 1024 kg, and the radius of the Earth is 6380 km.)
Physics
1 answer:
Yuri [45]3 years ago
8 0

Answer:

The answer is "83.1%".

Explanation:

Given:

\text{Mass of the earth}\  (M_E) = 5.97 \times 10^{24}\ \ kg\\\\\text{Radius of the earth}\ (R_E) = 6380 \ km = 6.38 \times 10^{6}\ \ m\\\\\text{acceleration of gravity}\  (g_E) = 608 \ \ km= 608,000 \ \ m \\\\G= 6.67 \times 10^{-11} \ \ \frac{N \cdot n^2}{kg^2}

Using formula:

\to g_E = G \frac{M_E}{(R_E +h)^2}

\to g_{608 \ km}=6.67\times10^{-11}\frac{5.97 \times 10^{24}}{(6.38 \times 10^{6}+ 608,000)^2}\\\\\to g_{608 \ km}=6.67\times10^{-11}\frac{5.97 \times 10^{24}}{(6,380,000+ 608,000)^2}\\\\\to g_{608 \ km} =6.67\times10^{-11}\frac{5.97 \times 10^{24}}{(6,380,000+ 608,000)^2}\\\\\to g_{608 \ km}=6.67\times10^{-11}\frac{5.97 \times 10^{24}}{(6,988,000)^2}\\\\\to g_{608 \ km}=6.67\times10^{-11}\frac{5.97 \times 10^{24}}{4.88 \times 10^{13}}\\\\

\to g_{608 \ km}=6.67\times10^{-24}\frac{5.97 \times 10^{24}}{4.88}\\\\\to g_{608 \ km}=6.67\times \frac{5.97}{4.88}\\\\\to g_{608 \ km}=6.67\times 1.22336066\\\\\to g_{608 \ km}= 8.15 \ \frac{m}{s^2}

Calculating the gravity on the Earth’s surface:

\to \frac{g_{608 \ km} }{ g_{\ earth \ surface}} = \frac{8.15}{9.8} \times 100=83.1 \%

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insens350 [35]

Answer:

Explanation:

a ) x ( t ) = t³ / 3 - t² + t

v = dx / dt = 3 t² / 3 - 2 t + 1 = t² -  2 t + 1

b ) lizard is at rest , v( t ) = 0

t² -  2 t + 1  = 0

( t - 1 )² = 0

t = 1

c )

velocity is positive when

t² -  2 t + 1  > 0

( t - 1 ) ² > 0

Here we see that LHS is a square so it is always positive whatever be the value of t

So velocity is always positive or lizard is always moving in positive x direction .

d ) It never moves in negative x direction .

e )

a ( t ) = dv / dt = 2t - 2

t = 1

so it has zero acceleration at t = 0 .

7 0
3 years ago
Which elements has the smallest first ionization energy?
Setler [38]

Answer:

Cesium has smallest ionization energy.

Explanation:

Ionization energy is the energy that an atom at ground state must be absorb to release an electron to form a cation. for eg.

H ⇒ H^{+} + e^{-}

The unit of ionization energy is \frac{KJ}{mol}.

The ionization energy is minimum for cesium  & maximum for fluorine.

Ionization energy depends upon the radius of atom. cesium has smallest radius so it has low Ionization energy.

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4 years ago
When the cylinder is displaced slightly along its vertical axis it will oscillate about its equilibrium position with a frequenc
Nesterboy [21]

Answer:

w = √[g /L (½ r²/L2 + 2/3 ) ]

When the mass of the cylinder changes if its external dimensions do not change the angular velocity DOES NOT CHANGE

Explanation:

We can simulate this system as a physical pendulum, which is a pendulum with a distributed mass, in this case the angular velocity is

          w² = mg d / I

In this case, the distance d to the pivot point of half the length (L) of the cylinder, which we consider long and narrow

         d = L / 2

The moment of inertia of a cylinder with respect to an axis at the end we can use the parallel axes theorem, it is approximately equal to that of a long bar plus the moment of inertia of the center of mass of the cylinder, this is tabulated

        I = ¼ m r2 + ⅓ m L2

        I = m (¼ r2 + ⅓ L2)

now let's use the concept of density to calculate the mass of the system

        ρ = m / V

        m = ρ V

the volume of a cylinder is

         V = π r² L

          m =  ρ π r² L

let's substitute

        w² = m g (L / 2) / m (¼ r² + ⅓ L²)

        w² = g L / (½ r² + 2/3 L²)

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When the mass of the cylinder changes if its external dimensions do not change the angular velocity DOES NOT CHANGE

4 0
4 years ago
What are some issues that governments must consider before passing conservation policies? Check all that apply.
Otrada [13]

Answer: cost to implement conservation policies

environmental implications

benefit versus the cost

Explanation:

The conservation policies involves certain instructions which are required to be followed by the human society at all levels so as to conserve resources and protect them for future. The following are the issues which government should be consider before passing the conservation policies this includes:

1. cost to implement conservation policies : The procedure and expenditure for the implementation of the policies should be under control of the desired budget so that the plan can be efficiently executed.

2.environmental implications : The government should be concerned about the implication of the policies on the environment. For example the preservation of an endangered species in control condition from an ecosystem can disturb the overall balance of an ecosystem.

3.benefit versus the cost: The government should concern before expending on the implementation of the policies the benefits and costs of the desired policies.

7 0
3 years ago
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Consider a mass-spring system. The spring has a spring constant 2.17e 3 N/m. On the end is a mass of 4.71 kg. You start at equil
Novosadov [1.4K]

Answer:

7.4 cm

Explanation:

K = 2.17 x 10^3 N/m

m = 4.71 kg

v = 1.78 m/s (It is maximum velocity)

The angular velocity

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\omega =\sqrt{\frac{2.71\times 10^{3}}{4.71}}

ω = 24 rad/s

Maximum velocity, v = ω x A

Where, A be the maximum displacement

1.78 = 24 x A

A = 0.074 m = 7.4 cm

8 0
4 years ago
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