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lidiya [134]
4 years ago
11

An undersea research chamber is spherical with an external diameter of 5.50 m . The mass of the chamber, when occupied, is 87600

kg . It is anchored to the sea bottom by a cable. The density of seawater is 1025 kg/m3. Part A What is the buoyant force on the chamber?
Physics
1 answer:
dmitriy555 [2]4 years ago
4 0

Answer:

the buoyant force on the chamber is F = 7000460 N

Explanation:

the buoyant force on the chamber is equal to the weight of the displaced volume of sea water due to the presence of the chamber.

Since the chamber is completely covered by water, it displaces a volume equal to its spherical volume

mass of water displaced = density of seawater * volume displaced

m= d * V , V = 4/3π* Rext³

the buoyant force is the weight of this volume of seawater

F = m * g = d * 4/3π* Rext³ * g

replacing values

F = 1025 kg/m³ * 4/3π * (5.5m)³ * 9.8m/s² = 7000460 N

Note:

when occupied the tension force on the cable is

T = F buoyant - F weight of chamber  = 7000460 N - 87600 kg*9.8 m/s² = 6141980 N

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Answer:

A. 1222,10 N

Explanation:

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Have a nice day! :D

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Fynjy0 [20]
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The "First Quarter" has that name because it's one quarter of the time
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3 0
3 years ago
Read 2 more answers
Recall the relationship between the charge on a capacitor and the potential difference across the capacitor. Use this relationsh
charle [14.2K]

Answer:

Answer in explanation.

Explanation:

The relationship between the charge on the capacitor and the potential difference across it is given as follows:

Q = CV

where,

Q = Charge on the Capacitor

C = Capacitance of the Capacitor

V = Potential Difference across the Capacitor

This relationship can be used to find the charge on a capacitor, using the voltmeter, as follows:

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8 0
3 years ago
what is the focalength of the combination of two thin renses of power -5D and -2D placeci in contact with each other?​
Ghella [55]

Answer:

f = - 0.143 m = - 14.3 cm

Explanation:

First, we will calculate the power of the combination of lenses:

P = P₁ + P₂

where,

P = Power of Combination = ?

P₁ = Power of first lens = - 5D

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Therefore,

P = - 5D - 2D

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Now, the focal length can be given as:

f = \frac{1}{P} \\\\f = \frac{1}{-\ 7\ D} \\\\

<u>f = - 0.143 m = - 14.3 cm</u>

Negative focal length indicates that combination will act as diverging lens.

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3 years ago
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