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2 years ago

Scientific notation of 45,000

Mathematics

2 answers:

babymother [125]2 years ago

7 0

Answer: 4.5 * 10^4

Step-by-step explanation:

tangare [24]2 years ago

7 0

Answer:

4.5 x 10^4

Step-by-step explanation:

move the decimal place 4 times:

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I need help with this if anyone can help

Fiesta28 [93]

Answer: $\Large\boxed{Fourth~Choice.~f(x)=2-i}$

Concept:

Here, we need to know the power of imaginary numbers

i = √(-1)

i² = -1

i³ = -i

i⁴ = 1

Solve:

Given function expression

$f(x)=x^3-2x^2$

Given the requirement of the question

To find the expression for f(i)

Substitute values into the expression

$f(x)=(i)^3-2(i)^2$

Simplify the exponents

$f(x)=(-i)-2(-1)$

Expand the parenthesis

$f(x)=-i-(-2)$

$\Large\boxed{f(x)=2-i}$

Hope this helps!! :)

Please let me know if you have any questions

3 0

1 year ago

Read 2 more answers

Let us have four distinct collinear points $a,$ $b,$ $c,$ and $d$ on the cartesian plane. the point $c$ is such that $\dfrac{ab}

Deffense [45]

Start with a line segment connecting two points, A and B. $\dfrac{DA}{BA}=3$ means DA is 3 times longer than BA. Clearly, D cannot fall between A and B because that would mean DA is shorter than BA. So there are two possible locations where D can be placed on the line relative to A and B.

But with $\dfrac{DB}{BA}=2$ , or the fact that DB is 2 times longer than BA, we can rule out one of these positions; referring to the attachment, if we place D to the left of A, then DB would be 4 times longer than BA.

Finally, $\dfrac{AB}{CB}=\dfrac12$ , so that CB is 2 times longer than AB. Again we have two possible locations for point C (it cannot fall between A and B), but one of them forces C to occupy the same point as D. However, A, B, C, D are distinct, so C must fall to the left of A.

Now let $d$ be the length of AB. Then the length of CD in terms of $d$ is $4d$ . We have the coordinates of C and D, and the distance between them is $\sqrt{(4-0)^2+(0-4)^2}=4\sqrt2$ . So

$4d=4\sqrt2\implies d=\sqrt2$

The slope of the line through C and D is

$\dfrac{0-4}{4-0}=-1$

and so the equation of the line through these points is

$y-4=-(x-0)\implies x+y=4$

So the coordinates of A are $(x,y)=(x,4-x)$ . The distance between C and A is $d=\sqrt2$ , so we have

$\sqrt{(x-0)^2+(4-x-4)^2}=\sqrt{2x^2}=|x|\sqrt2=\sqrt2\implies|x|=1$

Since A falls to the right of C (in the $x,y$ plane, not just in the sketch), we know to take the positive value $x=1$ . Then the $y$ coordinate is $y=4-1=3$ .