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Lerok [7]
3 years ago
6

Scientific notation of 45,000

Mathematics
2 answers:
babymother [125]3 years ago
7 0

Answer: 4.5 * 10^4

Step-by-step explanation:

tangare [24]3 years ago
7 0

Answer:

4.5 x 10^4

Step-by-step explanation:

move the decimal place 4 times:

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Solve the following system in any of the methods you prefer. (graphing, substitution, eliminating)
aleksandr82 [10.1K]
-3x -8y = -23
4(7x + 2y = -13)

-3x -8y = -23
28x + 8y = -52

25x = -75

x = -3

-3(-3) - 8y = -23
9 - 8y =-23
32 = 8y

y=4
6 0
3 years ago
A man and a woman agree to meet at a cafe about noon. If the man arrives at a time uniformly distributed between 11:40 and 12:10
kompoz [17]

Answer:

0.3888

Step-by-step explanation:

To solve the exercise we need a neutral time, so we define at 12:00 as time 0.

If the man arrives in a uniformly distributed time between 11:40 and 12:10, the time is distributed from -20 to 10.

If the woman arrives in a time evenly distributed between 11:45 and 12:20, the time is distributed from -15 to 20.

Assuming that each one arrives at 12: X and 12: Y for men and women, then the space of our time is defined as

Man [-20,10]

Woman [-15,20]

So,

f_x(x)=\frac{1}{10-(-20)}=\frac{1}{30}\\f_y(y)=\frac{1}{20-(-15)}=\frac{1}{35}

Then,

f_{xy}(x,y)=f_x(x)f_y(y)=\frac{1}{30} \frac{1}{35} = \frac{1}{1050}

The probability of finding an arrival less than 5 minutes is

P(|X-Y|\leq 5) = \int\limit^20_{-15} \int\limit^{x+5}_{x-5} f(x,y)dydx

P(|X-Y|\leq 5)= \frac{1}{1050}\int\limit^{20}_{-15} y|^{x+5}_{x-5}dx

P(|X-Y|\leq 5)= \frac{35*10}{900}=0.3888

6 0
3 years ago
At the beginning of year 1, Bode invests $250 at an annual simple interest rate of 3%. He makes no deposits to or withdrawals fr
Dennis_Churaev [7]
The initial investment = $250
<span>annual simple interest rate of 3% = 0.03
</span>
Let the number of years = n
the annual increase = 0.03 * 250
At the beginning of year 1 ⇒ n = 1 ⇒⇒⇒ A(1) = 250 + 0 * 250 * 0.03 = 250

At the beginning of year 2 ⇒ n = 2 ⇒⇒⇒ A(2) = 250 + 1 * 250 * 0.03
At the beginning of year 3 ⇒ n = 3 ⇒⇒⇒ A(2) = 250 + 2 * 250 * 0.03
and so on .......
∴ <span>The formula that can be used to find the account’s balance at the beginning of year n is:
</span>
A(n) = 250 + (n-1)(0.03 • 250)
<span>At the beginning of year 14 ⇒ n = 14 ⇒ substitute with n at A(n)</span>
∴ A(14) = 250 + (14-1)(0.03*250) = 347.5

So, the correct option is <span>D.A(n) = 250 + (n – 1)(0.03 • 250); $347.50 </span>
4 0
3 years ago
Read 2 more answers
Compare Partial Products And Regrouping. Describe How The Methods Are Alike And Different.
lisov135 [29]
U have too Cary the number for re gegrouping and I do not know what partial products are
6 0
3 years ago
Finding Value of Function
Anestetic [448]

Answer:

b

Step-by-step explanation:

fx+3

4 0
3 years ago
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