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kumpel [21]
4 years ago
5

Which of the following correctly represents the transmutation in which a curium-242 nucleus is bombarded with an alpha particle

to produce a californium-245 nucleus?^242_96 Cm(^1_0 n, ^4_2 He)^245_98 Cf^242_96 Cm(^4_2 He, ^1_1 p)^245_98 Cf^242_96 Cm(^4_2 He, 2^1_1 p)^245_98 Cf^242_96 Cm(^4_2 He, ^1_0 n)^245_98 Cf^242_96 Cm(^4_2 He, ^1_-1 e)^245_98 Cf
Chemistry
1 answer:
Alekssandra [29.7K]4 years ago
6 0

<u>Answer:</u> The chemical equation is written below.

<u>Explanation:</u>

Transmutation is defined as the process in which one chemical isotope gets converted to another chemical isotope. The number of protons or neutrons in the isotope gets changed.

The chemical equation for the reaction of curium-242 nucleus with alpha particle (helium nucleus) follows:

_{96}^{242}\textrm{Cm}+_4^2\textrm{He}\rightarrow _{98}^{245}\textrm{Cf}+_0^1\textrm{n}

The product formed in the nuclear reaction are californium-245 nucleus and a neutron particle.

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H2SO4 + 2NaNO2 → 2HNO2 + Na2SO4
dem82 [27]
<h3>Answer:</h3>

23.459 g NaNO₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Stoichiometry</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN] H₂SO₄ + 2NaNO₂ → 2HNO₂ + Na₂SO₄

[Given] 24.14714 g Na₂SO₄

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol Na₂SO₄ = 2 mol NaNO₂

Molar Mass of Na - 22.99 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of Na₂SO₄ - 2(22.99) + 32.07 + 4(16.00) = 142.05 g/mol

Molar Mass of NaNO₂ - 22.99 + 14.01 + 2(16.00) = 69.00 g/mol

<u>Step 3: Stoichiometry</u>

  1. Set up:                              \displaystyle 24.14714 \ g \ Na_2SO_4(\frac{1 \ mol \ Na_2SO_4}{142.05 \ g \ Na_2SO_4})(\frac{2 \ mol \ NaNO_2}{1 \ mol \ Na_2SO_4})(\frac{69.00 \ g \ NaNO_2}{1 \ mol \ NaNO_2})
  2. Multiply/Divide:                                                                                                \displaystyle 23.4587 \ g \ NaNO_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We need 5 sig figs (instructed).</em>

23.4587 g NaNO₂ ≈ 23.459 g NaNO₂

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