1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aivan3 [116]
3 years ago
15

Rank the following from most metallic to least metallic:

Chemistry
1 answer:
Svetach [21]3 years ago
4 0

Answer:

Cs > Iron > Aluminum > Carbon > Neon

Explanation:

The most metallic from the given choices is Cesium and the least metallic is Neon.

Neon is noble gas and not a solid.

Metallic character of elements decreases across the period and increases with increasing electronegativity.

The most leftward element is Cesium and will be the most metallic. Neon has the least metallic character since it is a noble gas.

    Cesium > Iron > Aluminum > Carbon > Neon

You might be interested in
Katie's teacher has asked her to identify an unknown
sleet_krkn [62]
The liquid freezes at 32 degrees celcius(A) is not the properties of water as water freezes at 0 degrees celcius
4 0
3 years ago
Write the balanced COMPLETE ionic equation for the reaction when
Vera_Pavlovna [14]

Answer:

Ba²⁺(aq) + 2 NO₃⁻(aq) + 2 Rb⁺(aq) + 2 OH⁻(aq) = Ba(OH)₂(s) + 2 Rb⁺(aq) + 2NO₃⁻(aq)

Explanation:

Let's consider the molecular equation between barium nitrate and rubidium hydroxide to produce barium hydroxide and rubidium nitrate.

Ba(NO₃)₂(aq) + 2 RbOH(aq) = Ba(OH)₂(s) + 2 RbNO₃(aq)

The complete ionic equation includes all the ions and the molecular species.

Ba²⁺(aq) + 2 NO₃⁻(aq) + 2 Rb⁺(aq) + 2 OH⁻(aq) = Ba(OH)₂(s) + 2 Rb⁺(aq) + 2NO₃⁻(aq)

3 0
3 years ago
The two naturally occurring isotopes of antimony, 121Sb (57.21 percent) and 123Sb (42.79 percent), have masses of 120.904 and 12
Alex

Answer:

The correct answer is option c.

Explanation:

Formula used to determine an average atomic mass :

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

Mass of isotope Sb-121 = 120.904 amu

Fractional abundance of Sb-121 = 57.21% = 0.5721

Mass of isotope Sb-123 = 122.904 amu

Fractional abundance of Sb-123 = 42.79% = 0.4279

Average atomic mass of Sb:

120.904 amu\times 0.5721+ 122.904 amu\times 0.4279=121.7598 amu \approx 121.76 amu

7 0
3 years ago
PLEASE HELP I WILL GIVE BRAINLIEST!!! Its due tonight at 12:00
Dmitry [639]

Answer:

c

Explanation:

we have only distance vs time graph so c is the right answer that cart is moving with constant speed of 0.5m/s

confirmed

first calculate distance which is from 2 to 5.5

5.5-2=3.5

apply the formula of velocity

v=s/t

v=3.5/7=0.5

8 0
3 years ago
Read 2 more answers
Rocky objects that are massive enough will have a spherical shape due to the force of gravity. (no links or else I will report y
Vesnalui [34]
“About 300 kilometers across have irregular shapes because their internal gravity is not strong enough to compress the rock into a spherical shape” so I’m guessing it’s false ?
5 0
3 years ago
Other questions:
  • Answer the question please
    14·1 answer
  • Why Sncl2 is solid but SnCl4 is liquid at room temperature
    15·1 answer
  • 9. An atom's electron configuration is shown here. How many electrons are in
    12·1 answer
  • why do these energy levels mean that the atom will show an emission spectrum of individual lines rather than a continuous spectr
    12·1 answer
  • What was the most likely problem with the first set of
    15·1 answer
  • Calculate the amount of energy when water at 72 degrees c freezes completely at 0 degrees c
    13·1 answer
  • What is the name of the ionic compound RbCI
    10·1 answer
  • Why is it useful to organize the data on a graph? Explain your answer.
    10·1 answer
  • Is alka seltzer and acid or a base or netural
    7·1 answer
  • Use Boyle's Law to interpret the following problem and then select the correct answer below.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!