Question

How many moles of gas does it take to occupy 120 L at a pressure of 233 kPa and a temperature of 340 K?

Answer 1

Answer:

The correct answer is option D.

Explanation:

Using ideal gas equation:

PV = nRT

where,

P = Pressure of gas = 233 kPa

1 atm = 101.325 kPa

$233kPa=\frac{233}{101.325} atm=2.30 atm$

V = Volume of gas = 120 L

n = number of moles of gas = ?

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 340 K

Putting values in above equation, we get:

$2.30 atm\times 120L=n\times (0.0821L.atm/mol.K)\times 340K\\\\n=9.88 mole\approx 9.9 mole$

Answer 2

A would be correct have a nice day.