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tiny-mole [99]
3 years ago
15

Because of the unexpected cold weather,the cost of tomatoes increased 50 percent in one month.If the cost after the increase was

60 cent per pond,what was the cost before the increase?
Mathematics
1 answer:
Tasya [4]3 years ago
5 0
A 50% increase is just taking the original amount and adding half of that towards the amount.

Example : 50% of 100 is 50 so a 50% increase to 100 would be 150

a formula for this would be X + (1/2×X) = Y

in your case we're working backwards with the known being 60

We can just plug in reasonable values for X until we get 60

50% of 40 is 20

40 + 20 = 60

so the original amount was 40

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there are 150 more passenger cars than trucks on the highway. for every 10 passenger cars there are 7 trucks. how many trucks ar
lora16 [44]

Answer:

500

Step-by-step explanation:

Given: P = 150 - T where P is passenger cars and T is trucks

10P = 7T ⇔ P = \frac{7T}{10}

Plug in equation 2 into equation 1:

\frac{7T}{10} = 150 - T

Solving for T, we get 500

5 0
3 years ago
Read 2 more answers
Slope of (1,3) and (4,9)
elena-s [515]

Answer:

slope = 2

Step-by-step explanation:

Calculate the slope m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (1, 3) and (x₂, y₂ ) = (4, 9)

m = \frac{9-3}{4-1} = \frac{6}{3} = 2

5 0
3 years ago
the width of a rectangle is 3 inches, and the area is 88 square inches. What are the length and width of the rectangle
inessss [21]

Answer:

length is 29.3, width is 3

Step-by-step explanation:

A= L×W

and if A = 88 and W is 3

88= L×3

Divide

88/3

legth =29.3

8 0
3 years ago
What is the area of a rectangle with length 36 cm and width 4 cm?
natita [175]

Answer:

A=144cm²

Length: 36cm

Width: 4cm

Step-by-step explanation:

36 x 4 = 144 cm

3 0
2 years ago
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What is the exact area and arc length of these sectors? Please helppp
Karolina [17]

<u>Answers with step-by-step explanation:</u>

1. Area of sector 1 = \frac{90}{360} \times \pi \times 12^2 = 36\pi

2. Area of sector 2 = \frac{45}{360} \times \pi \times 19^2 = \frac{2527}{8} \pi

3. Area of sector 3 = \frac{270}{360} \times \pi \times 15^2 = \frac{675}{4} \pi

4. Area of sector 4 = \frac{270}{360} \times \pi \times 6^2 = 27 \pi

5. Arc length of sector 1 = \frac{90}{360} \times 2 \times \pi \times 12 = 6\pi

6. Arc length of sector 2 = \frac{315}{360} \times 2 \times \pi \times 19 = \frac{133}{4} \pi

7. Arc length of sector 3 = \frac{270}{360} \times 2 \times \pi \times 15 = \frac{45}{2}\pi

8. Arc length of sector 4 = \frac{270}{360} \times 2 \times \pi \times 6 = 9\pi

4 0
3 years ago
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